Answer:
- see the attached for domain
- Range: (-∞, 4], [3, ∞), [-3, 1]
Step-by-step explanation:
The domain is the horizontal extent of the graph. When the graph has arrows on the end, it extends to infinity in the indicated direction.
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The range is the vertical extent of the graph.
<u>Left Graph</u>
We assume the curve is intended to touch, not cross, the line y=4, so the range is ...
range: (-∞, 4]
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<u>Middle Graph</u>
We assume the graph continues along the line y=3 to the right indefinitely. Then this value is the minimum of the range.
range: [3, ∞)
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<u>Right Graph</u>
The low point on the graph is at y=-3, and it looks like the graph continues to the right along the line y=1. Then the range is ...
range: [-3, 1]
Y=-1/2
Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.<span><span>(y)</span>⋅<span>(6)</span>=<span>(−3)</span>⋅<span>(1<span>)
</span></span></span>Simplify the left side.<span><span>6y=<span>(−3)</span>⋅<span>(1)</span></span><span>6y=<span>(-3)</span>⋅<span>(1)</span></span></span>
Simplify the right side.<span><span>6y=−3</span><span>6y=-3</span></span>
Divide each term by <span>66</span> and simplify.y=-1/2
Answer:
There are 42 red colour socks and 44 green color socks
Step-by-step explanation:
Let there are r red socks and g green socks.
ATQ,
He has three times times as many red socks subtracted from four times as many green socks which he believes is 50 socks.
4g-3r=50 ....(1)
Half the number of green socks plus one-third of the number of red socks is 36.
Multiply equation (1) by 2 and equation (2) by 3.
8g-6r = 100 ....(3)
9g +6r = 648 ....(4)
Add equation (3) and (4)
8g-6r + 9g +6r = 100+648
17g = 748
g = 44
Put the value of g in equation (1).
4(44)-3r=50
176-3r = 50
176-50 = 3r
r = 42
Hence, there are 42 red colour socks and 44 green color socks.
Answer:
A. 2, 2, 5
Step-by-step explanation:
<u>DE:</u>
BA = 10
10 * 1/5 = 2
<u>EF:</u>
BC = 10
10 * 1/5 = 2
<u>DF:</u>
AC = 25
25 * 1/5 = 5
Answer:
Play 3
Step-by-step explanation:
Given:
Required [Missing from the question]:
Determine the play with the least change in yard?
To do this, we ignore the sign in front of each yard before we analyze.
So, we have:
Play 1 has a change of 4
Play 2 has 6
Play 3 has 2
Play 4 has 3
<em>From the above analysis, play has the least (which is 2)</em>
