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3 years ago

When comparing the two sets of data, what is a true statement

Mathematics

2 answers:

PolarNik [594]3 years ago

4 0

Answer:

Step-by-step explanation:

timurjin [86]3 years ago

3 0

Answer:

the answer is b

Step-by-step explanation:

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find the value of 10 times the square root of 2 over the square root of 5.. a. 2 b. 2 times the square root of 5. c. 2 the squar

Marizza181 [45]

$\dfrac{10\sqrt2}{\sqrt5}=\dfrac{10\sqrt2\cdot\sqrt5}{\sqrt5\cdot\sqrt5}=\dfrac{10\sqrt{2\cdot5}}{5}=\boxed{2\sqrt{10}}\to\fbox{c.}$

6 0

2 years ago

Help! I don't understand this

Murljashka [212]

The area of your circle is about 530.93 m

The diameter of your circle is 26 m, just multiply your radius by 2

The circumference of the circle is about 81.68

The equation to finding the area is

pi x r x 2

3.14 times 13 times 2

The equation to finding the diameter

r x 2

radius times 2

The equation for finding circumference

pi x d

3.14 times 26

Let me know if im wrong, otherwise I want brainliest, PLEASE!!

8 0

3 years ago

Lowest fraction using common term<br><br> 28/35

rjkz [21]

28/7=4
35/7=5
4/5
A: 4/5

3 0

3 years ago

2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16

Masja [62]

Answer: $\frac{x-4}{2x-2}$

Step-by-step explanation:

$\frac{2x^2+5x+3}{x^2-3x-4}$ divided by $\frac{4x^2+2x-6}{x^2-8x+16}$ is the same thing as multiplying $\frac{2x^2+5x+3}{x^2-3x-4}$ by $\frac{x^2-8x+16}{4x^2+2x-6}$ .

The equation we get is:

$\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}$

With this equation, we can factor each equation:

$\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}$

We can cancel out like terms since they would be dividing each other:

$\frac{x-4}{2x-2}$

8 0

3 years ago

100 POINTS ANSWER FAST NO BEGINNERS OR AMBITIOUS, VIRTUOSO AND UP ONLY

Flauer [41]

I hope this helps you

8 0

3 years ago

Read 2 more answers