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3 years ago

How do i solve thissss (mainly the question on the bottom)

Mathematics

1 answer:

Ymorist [56]3 years ago

6 0

well done

well, a function for a relationship means, the x-coordinates must not repeat in a set, namely that for every "y" there must be a unique "x" coordinate, no X-REPEATS.

so for example in a relation that say is { (3, 4) , (5, 4) , (7, 4) , (10, 11) }, we do have y-coordinates repeated, but for a function that doesn't matter, our x-coordinates are not repeated thus, it's a function.

in this case, let's see the relationship set, just a few points { (3,5) , (3,6) , (3,8) , (6,10)}, well darn, we have 3 repeated three times in the x-coordinate slots, therefore is not a function, just a relation.

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A triangle has an area of 80 yd^2 and a height of 10 yd. How long is the base of a triangle? Enter in the answer in the box.

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Answer:

Length of the base is 16 yards.

Step-by-step explanation:

We are given that,

Area of the triangle = 80 yd²

Height of the triangle = 10 yards

Since, we know,

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So, we get,

$80=\frac{1}{2}\times Base \times 10$

i.e. $80=Base \times 5$

i.e. $Base=\frac{80}{5}$

i.e. Base = 16 yards

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Solve: (-5/6) × (9/20) + (-5/6) × 7/25 = ?

jonny [76]

$\bf \underline{★ How \:to\: do -} \\$

Here, we are given with four fractions to multiply two of them and to add two of them. If we add them directly by taking the LCM and adding them is not a similar way. We can clearly observe that in those four fractions, we have two fractions as common i.e, we have two fractions as same. If we have two fractions or numbers as same, we can solve the sum by an other concept called as distributive property. In this property, we multiply the common fraction with the sum of other two fractions. This concept can also be done with fractions as well as integers. So, let's solve!!

$\:$

$\bf \underline{➤ Solution-} \\$

${\tt \leadsto \dfrac{(-5)}{6} \times \dfrac{9}{20} + \dfrac{(-5)}{6} + \dfrac{7}{25}}$

Group the non-common fractions in bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9}{20} + \dfrac{7}{25} \bigg)}$

First we should solve the numbers in bracket.

LCM of 20 and 25 is 100.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9 \times 5}{20 \times 5} + \dfrac{7 \times 4}{25 \times 4} \bigg)}$

Multiply the numerators and denominators in the bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45}{100} + \dfrac{28}{100} \bigg)}$

Now, write both numerators in bracket with a common denominator.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45 + 28}{100} \bigg)}$

Now, add the numerators in bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{73}{100} \bigg)}$

Write the numerator and denominator in lowest form by cancellation method.

${\tt \leadsto \dfrac{\cancel{(-5)} \times 73}{6 \times \cancel{100}} = \dfrac{(-1) \times 73}{6 \times 20}}$

Now, multiply the numerators and denominators.

${\tt \leadsto \dfrac{(-73)}{120}}$

$\:$

${\red{\underline{\boxed{\bf So, \: the \: answer \: obtained \: is \: \: \dfrac{(-73)}{120}}}}}$

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Graphing this, the parabola is not moved from the parent graph f(x) = x², but the graph is compressed horizontally by a factor of 4.Step-by-step explanation:

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