Answer:
D.
Step-by-step explanation:
If you would rotate RN until R meets L it would exactly overlap with FL. So RN=FL.
Answer:
88.51 is the minimum score needed to receive a grade of A.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 73
Standard Deviation, σ = 11
We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.0793.
Calculation the value from standard normal z table, we have,

Hence, 88.51 is the minimum score needed to receive a grade of A.
The first, third, and sixth are correct.
According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

Here, n is equal to 66 and by substituting the value to the equation we get:

k = 7.0444
k ≈ 7
Learn more about Sturge's rule here: brainly.com/question/28184369
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First understand that this is a linear graph. Find 2 points on the graph. We can use (0,1) and (3,-3).
Look at how much the x increases, in this case the x value increases by 0+3, so 3.
Then see how much the y value increases (make sure to evaluate them in the same order) 1 + (-3) = -2.
So you know that the y value decreases by 2 units for every 3 unit increase in x. Therefore the slope is y=(-2/3)x
Then figure out what you add to the end. The y intercept is (0,1), so add 1 to the end of y=(-2/3)x to move it up.
Your resulting eq is y=(-2/3)x+1