Answer: we dont have options
Step-by-step explanation:
Beaded braclets at 9 beads each
Then 156 beads = 156/9
17.333
But the answer is 17 braclets since she cannot make .333 of a braclet
Answer: x=12, x=-3
Step-by-step explanation: For this factored problem, you see that -36 is negative, as well at -9. This shows you that you need to find two numbers that multiply to get -36, and add up to get -9. Two numbers that both satisfy these requirements are -12 and 3. They multiply to get -36, and add to get -9.
Once you have found your values, you plug them into (x+/- __)(x+/- __), which is (x-12)(x+3).
But since the problem asks you to find the zeroes, you set each factor equal to zero, like this:
x-12=0 and x+3=0
Then solve and you have you answer!
<u>Answer & Step-by-step explanation:</u>
<u>Question 18 </u>
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form: x ≤ −10
Interval Notation: (−∞ , −10]
<u>Question 19</u>
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form: x ≤ 4
Interval Notation: (−∞ , 4]
Answer:
A = 80 S =70
Step-by-step explanation:
#Adults tickets = A
#Students tickets = S
A + S = 150
5A (means the price is $5 times the number of Adult tickets) equals the total amount for all of the Adult tickets altogether
3S (means the price is $3 times the number of Student tickets) equals the total amount for all of the students tickets altogether
5A + 3S = 610 (Means adding the total of all the student tickets plus adult tickets will equal $610 for all tickets sold)
Using both equations now, you can use substitution or elimination to solve for one of the variables. Then you can use the variable to substitute to solve the remaining one.
A + S = 150
5A + 3S = 610
Substitution:
A = 150 - S (Rearrange the first equation by moving S to the other side)
Substitute into the other equation
5 (150 - S) + 3S = 610
750 - 5S + 3S = 610 Combine like terms : -2S = -140
Solve for S = 70
Substitute into A + S = 150 A + (70) = 150
A = 80
