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3 years ago

Solve for x and y!!

Mathematics

1 answer:

Evgen [1.6K]3 years ago

8 0

Answer:

Step-by-step explanation:

4y - 16 + 68 = 180

4y + 52 = 180

4y = 128

y = 32

2x - 24 = 68

2x = 92

x = 46

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Geometry! helpp me please <3

STatiana [176]

Answer:

the answer is a

Step-by-step explanation:

7 0

3 years ago

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

The coordinates are given as:

$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

Square both sides

$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

$\mathbf{b^2 = 1100}$

The equation of an hyperbola is:

$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

So, we have:

$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

$\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Hence, the equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Read more about hyperbolas at:

brainly.com/question/15697124

7 0

3 years ago

Read 2 more answers

A rectangular prism has a base of 18 cm by 15 cm and a diagonal of 25 cm. Identify its height. Round to the nearest tenth. HELP

jok3333 [9.3K]

Answer:

8.7 cm

Step-by-step explanation:

You know the relationship between the diagonal of a rectangular prism and the sides as $d^2 = x^2 + y^2 + z^2$ where x, y and z are the three dimensions of the prism. from your data, $25^2 =18^2 + 15^2 + z^2$ or $z^2 = 25^2 -18^2 - 15^2$ . With some simple calculation you get $z^2 = 625 - 324 - 225 = 76$ , or $z= 8.7178....$