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Marysya12 [62]
3 years ago
15

How to change a bianary number into decimal number​

Mathematics
2 answers:
adelina 88 [10]3 years ago
6 0

1. Positional Notation

2. Doubiling

3. An Online Converter

wariber [46]3 years ago
6 0

Step-by-step explanation:

Hey there!!!

We generally multiply using base 2 and keep power that starts from 0 and goes on increasing and add all them at last to convert binary to decimal.

For example:

011110

To convert into decimal follow the steps.

1st step: Multiply with base 2 and keep power from right side starting from 0.

0 \times  {2}^{5}  + 1 \times  {2}^{4} + 1 \times  {2}^{3}   + 1 \times  {2}^{2}  + 1 \times  {2}^{1}  + 0 \times  {2}^{0}

2nd step: solve powers and multiply with binary numbers.

This implies;

= 0 + 16 + 8 + 4 + 2 +0

= 30.... is your answer.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Answer:

a) The 98% confidence interval would be given (0.182;0.218).

b) We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

c) If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

d) Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

Step-by-step explanation:

Data given and notation  

n=2700 represent the random sample taken    

X represent the people in England who are deficient in Vitamin D

\hat p=0.2 estimated proportion of England people who are deficient in Vitamin D

\alpha=0.02 represent the significance level

Confidence =0.98 or 98%

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p= population proportion of England people who are deficient in Vitamin D

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.33

And replacing into the confidence interval formula we got:

0.20 - 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.182

0.20 + 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.218

And the 98% confidence interval would be given (0.182;0.218).

Part b

We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

Part c

If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

Part d

Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

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Answer:

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ch4aika [34]
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65/5 = 5x/5

13 = x

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