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3 years ago

How do I do this? can someone please help me

Mathematics

2 answers:

hodyreva [135]3 years ago

6 0

Answer:

P = -4, 3

Step-by-step explanation:

Locate the x-axis (horizontal) location of point P, starting from zero

Point P's x-axis = -4

Now locate the y-axis (vertical) location of point P, starting from zero

Point P's y-axis = 3

Combine the two axes in a coordinate equation.

Point P = (-4, 3)

Note that zero is located at the intersection of the two axes.

Kamila [148]3 years ago

4 0

Answer:

(-4,3)

Step-by-step explanation:

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3 years ago

Rachel plays a game by rolling two number cubes with sides numbered 1 through 6 to win the game the sum of the numbers facing up

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The probability that Rachel will win the game is: 1/12

Step-by-step explanation:

The number cubes has six sides numbered between 1 to 6. the chances of each number are equally likely

Let S be the sample space

The sample space has 6*6 = 36 outcomes.

Now, Let A be the event that the sum of numbers on both number cubes is 10

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7 0

3 years ago

Who can help me answer this question ASAP please and thank you please show work

kotegsom [21]

I'll do the first one to get you started

So we have g(f(x)) which means that we start with g(x) and replace the 'x' with 'f(x)' to get g(f(x))

g(x) = ( x - 4 )/2

g(f(x)) = ( f(x) - 4)/2 .... replace every x with f(x)

g(f(x)) = (2x+4-4)/2 .... replace f(x) on the right side with 2x+4

g(f(x)) = (2x+0)/2

g(f(x)) = (2x)/2

g(f(x)) = 1x/1

g(f(x)) = 1x

g(f(x)) = x

Let me know if you need help with the other one.

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3 years ago

Order 0.709, 0.710, 0.79, and 0.079 from smallest to largest.

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0.079, 0.709, 0.710, 0.79

You will have to look at the placement of each digit.

In this case, after the decimal point:
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hundredths is next (the number directly to the right of the tenths place)
thousands is the smallest (in this case, next to the hundreds place)

hope this helps

3 0

3 years ago

Read 2 more answers

Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus

Ksivusya [100]

Given:

The given equation is:

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