Solve the system of equations 3x – 2y + 4z = -14 -4x + y + 4z = -16 -3x - y - 4z = 2
1 answer:
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Answer:
We draw line AB which is perpendicular to the 14 cm side
Since Angle C is 60 degrees that makes angle CAB = 30 degrees
Triangle CAB is a 30 60 90 triangle so line CB is half the hypotenuse or 5 cm
Line BD equals 9 cm
Line AB^2 = 10^2 - 5^2 = 75
Line AD^2 = AB^2 + BD^2
Line AD^2 = 75 + 81
Line AD^2 = 156
Line AD = 12.4899959968
Line AB = Sqr root (75) = 8.6602540378
Angle D = arc sine (8.6602540378 / 12.4899959968)
Angle D = 43.898 degrees
Angle A = 180 - 60 - 43.898 = 76.102 degrees
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Actually this could have been done a little easier by using the Law of Cosines and then the Law of Sines, but I just thought I'd show another way to solve this.
Step-by-step explanation:
Answer:
Answer is in the attachment
Answer:
x = 24
Step-by-step explanation:
ABCD is a parallelogram.
Angle B and Angle C are adjacent (successive) angles.
Adjacent angles of a parallelogram are supplementary.
Therefore,