Answer:
Area of sector ≈ 15.6π (nearest tenth)
Step-by-step explanation:
Given:
radius = 5 cm
Central angle in radians = ∅ = 5π/4
Required:
Area of the sector
Solution:
Area of sector = ½*r²*∅
Plug in the values into the formula
Area of sector = ½*5²*5π/4
= ½*25*5π/4
= 12.5*5π/4
= (12.5*5π)/4
Area of sector = 15.625π ≈ 15.6π (nearest tenth)
Answer:
see the picture
Step-by-step explanation:
you can use geogebra to help you
Answer:
Step-by-step explanation:
Please refer to the image attached.
Here we have a circle with unit radius. At some angle Ф the radius = 1 , and it is the hypotenuse (shown by green line in the image attached) of the ΔPQR thus formed. As our angle Ф increases, the hypotenuse gets closer to the positive y axis and at 90°, it overlap the y axis. Hypotenuse (H) and Opposite site (O) becomes same and Adjacent (A) becomes 0.
As our angle move further and reaches 180, the Hypotenuse and adjacent becomes same and overlap negative x axis. As we move further at 270 i.e , the hypotenuse and opposite side overlap on y axis and Adjacent side become 0. However the opposite side becomes negative here .
Our sine ratio says
Hence we have our
Now
Adjacent as we discussed is 0 at
NO THIS IS NOT A FUNCTION THEIR IS 2 X VALUES THAT ARE 13