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lisabon 2012 [21]
3 years ago
14

Question is shown below, please help!

Mathematics
1 answer:
Reika [66]3 years ago
7 0
I think it -4 hope this helps
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SUPER EASY MATH PROBLEM IM JUST DUMB, WILL MARK BRAINLIEST. PLEASE HELP
worty [1.4K]

Answer:

m<1 = 105°

m<2 = 75°

very simple explanation:

a and b are perpendicular. line t intersects these perpendicular lines. the given 75° is, in short, an intersect of a line, which is 180°. 75-180=105. angles 1 and 2 are duplicates of what is shown

8 0
3 years ago
A business owner collected data on the people working for her company. She determined the average number of minutes each employe
Naddika [18.5K]

Answer:

The comparison using median and IQR is best because one of the graphs is not symmetrical.<em> </em>

Step-by-step explanation:

The following information is missing

<em>A box plot titled Number of Minutes Women Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 54, and the box ranges from 34 to 50. A line divides the box at 48.  </em>

<em>A box plot titled Number of Minutes Men Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 68, and the box ranges from 36 to 60. A line divides the box at 48.  </em>

<em>The business owner uses the median and IQR to determine the center and variability of the data sets. Which best describes the comparison? </em>

<em>The comparison would be more accurate using the mean and MAD because one of the graphs is symmetric. </em>

<em>The comparison would be more accurate using the mean and MAD because the median of both data sets is the same. </em>

<em>The comparison using median and IQR is best because one of the graphs is not symmetrical. </em>

<em>The comparison using median and IQR is best because the median is greater than the IQR for both data sets.</em>

<em />

Mean and MAD are useful for comparison when both data sets are symmetrical.

In the women box plot the Q1 is at 34, the median is at 48, and the Q3 is at 50, so it is not symmetrical (the difference between the median and the Q1, and the Q3 and the median is not the same)

8 0
3 years ago
Mixed number as a decimal 7 9/18
Lesechka [4]

Answer:

3.5

Step-by-step explanation:

7 0
3 years ago
Find the center and radius of this circle x^2+y^2-6x-10y+30=0
Artist 52 [7]

Answer:

Center: (3,5)

Radius: 2

Step-by-step explanation:

x² + y² - 6x - 10y + 30 = 0

Put equation into center-radius form. First regroup terms:

(x²-6x) + (y²-10y) = -30

Complete the squares:

(x²-6x+3²) + (y²-10y+5²) = -30 + 3² + 5²

(x-3)² + (y-5)² = 4 = 2²

Center: (3,5)

Radius: 2

8 0
2 years ago
Help me pleaseeee ???
Leokris [45]
There's only one solution...the one you get when you divide both sides by 22 to solve for x.  902/22 = 41.  That exponent on the x, the one you don't see, is a "1" which tells us that there is only 1 solution to this problem.  If your x is squared, then you have 2 solutions; if it's cubed, you have 3, etc.
7 0
3 years ago
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