All categories

3 years ago

Please help me with this question image attached

Mathematics

1 answer:

algol [13]3 years ago

6 0

Answer:

Not enough information. For this to be SAS, the single tick mark would need to be located on the line CB and ED.

Step-by-step explanation:

You might be interested in

Evaluate 5x 2+ 2(4x – 7) – 8x for x = 3.

Sauron [17]

Answer:

10x-14

Step-by-step explanation:

6 0

3 years ago

I need help please.

inn [45]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
6.008 can be written as =

▪️6008 / 100
▪️6008 / 100
= 3004 / 50
= 1502 / 25
= 1502 / 25 in mixed fraction .
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
That’s it...

7 0

3 years ago

Ann works at a store in the mall and earns a wage of 8 dollars an hour. She earns 10 dollars an hour is she works on the weekend

soldier1979 [14.2K]

Answer:

The Answer is $352

Step-by-step explanation:

8 times 24 = 192

10 times 16 = 160

192 + 160 = 352

6 0

4 years ago

71/3 - 21/4 (2 1/5 × 3/4) with working

RideAnS [48]

Answer:

15 1/240

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the absolute extrema of f(x) = e^{x^2+2x}f ( x ) = e x 2 + 2 x on the interval [-2,2][ − 2 , 2 ] first and then use the com

fredd [130]

$f(x)=e^{x^2+2x}\implies f'(x)=2(x+1)e^{x^2+2x}$

$f$ has critical points where the derivative is 0:

$2(x+1)e^{x^2+2x}=0\implies x+1=0\implies x=-1$

The second derivative is

$f''(x)=2e^{x^2+2x}+4(x+1)^2e^{x^2+2x}=2(2x^2+4x+3)e^{x^2+2x}$

and $f''(-1)=\frac2e>0$ , which indicates a local minimum at $x=-1$ with a value of $f(-1)=\frac1e$ .

At the endpoints of [-2, 2], we have $f(-2)=1$ and $f(2)=e^8$ , so that $f$ has an absolute minimum of $\frac1e$ and an absolute maximum of $e^8$ on [-2, 2].

So we have

$\dfrac1e\le f(x)\le e^8$

$\implies\displaystyle\int_{-2}^2\frac{\mathrm dx}e\le\int_{-2}^2f(x)\,\mathrm dx\le\int_{-2}^2e^8\,\mathrm dx$

$\implies\boxed{\displaystyle\frac4e\le\int_{-2}^2f(x)\,\mathrm dx\le4e^8}$

5 0

3 years ago