I don't think anyone can solve this without seeing the table mentioned in the question :)
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
The 99 percent confidence interval for the true mean length of the bolt is CI = (2.8712, 3.1288)
<h3>How to find the confidence interval?</h3>
Confidence Interval is used to tell us the degree of certainty or uncertainty that is existent in a sampling method.
The general formula for confidence interval is;
CI = x' ± z(s/√n)
where;
x' is sample mean
z is z-score at confidence level
s is sample standard deviation
n is sample size
We are given;
sample size; n = 36
Sample mean; x' = 3 inches
standard deviation; s = 0.3 inches
confidence level = 99%
z at 99% CL = 2.576
Thus;
CI = 3 ± 2.576(0.3/√36)
CI = 3 ± 0.1288
CI = (2.8712, 3.1288)
Read more about Confidence Interval at; brainly.com/question/17097944
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Answer:
Step-by-step explanation:
B
Answer:
Y = 50x
Since every minute he jumps 50 times, we multiply 50 by the amount of minutes (x)
