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3 years ago

Please help me with this question image attached

Mathematics

1 answer:

algol [13]3 years ago

6 0

Answer:

Not enough information. For this to be SAS, the single tick mark would need to be located on the line CB and ED.

Step-by-step explanation:

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Three bouquets of flowers are ordered at a florist. 3 roses, 2 carnations, and 1 tulip cost $14. 6 roses, 2 carnations, and 6 tu

STALIN [3.7K]

cost of 1 rose = $ 3

cost of 1 carnation = $ 1

cost of 1 tulip = $ 3

<em><u>Solution:</u></em>

Let "r" be the cost of 1 rose

Let "c" be the cost of 1 carnation

Let "t" be the cost of 1 tulip

<em><u>3 roses, 2 carnations, and 1 tulip cost $14</u></em>

So we can frame a equation as:

3 roses x cost of 1 rose + 2 carnations x cost of 1 carnation + 1 tulip x cost of 1 tulip = $ 14

$3 \times r + 2 \times c + 1 \times t = 14$

3r + 2c + 1t = 14 ----- eqn 1

<em><u>6 roses, 2 carnations, and 6 tulips cost $38</u></em>

So we can frame a equation as:

6 roses x cost of 1 rose + 2 carnations x cost of 1 carnation + 6 tulip x cost of 1 tulip = $ 38

$6 \times r + 2 \times c + 6 \times t = 38$

6r + 2c + 6t = 38 ------ eqn 2

<u><em>1 rose, 12 carnations, and 1 tulip cost $18</em></u>

So we can frame a equation as:

1 rose x cost of 1 rose + 12 carnations x cost of 1 carnation + 1 tulip x cost of 1 tulip = $ 18

$1 \times r + 12 \times c + 1 \times t = 18$

r + 12c + t = 18 ----- eqn 3

<em><u>Let us solve eqn 1 and eqn 2 and eqn 3 to find values of "r" "c" "t"</u></em>

3r + 2c + 1t = 14 ----- eqn 1

6r + 2c + 6t = 38 ------ eqn 2

r + 12c + t = 18 ----- eqn 3

From eqn 1,

3r = 14 - 2c - t

$r = \frac{14 - 2c - t}{3}$

Substitute the above value of r in eqn 2

$6(\frac{14 - 2c - t}{3})+ 2c + 6t = 38\\\\28 - 4c - 2t + 2c + 6t = 38\\\\-2c +4t = 10\\\\-2c = 10 - 4t\\\\2c = 4t - 10\\\\c = 2t - 5$

Substitute c = 2t - 5 and $r = \frac{14 - 2c - t}{3}$ in eqn 3

$12(2t - 5) + \frac{14 - 2c - t}{3} + t = 18\\\\24t - 60 + \frac{14-2(2t - 5) - t}{3} + t = 18\\\\72t - 180 + 14 - 4t +10 - t + 3t = 54\\\\70t = 54 + 180 - 14 -10\\\\70t = 210\\\\t = 3$

Substitute t = 3 in c = 2t - 5

c = 2(3) - 5

Substitute t = 3 and c = 1 in $r = \frac{14 - 2c - t}{3}$

$r = \frac{14 - 2(1) - 3}{3}\\\\r = \frac{14 - 2 - 3}{3}\\\\r = \frac{9}{3} = 3$

<em><u>Summarizing the results:</u></em>

cost of 1 rose = $ 3

cost of 1 carnation = $ 1

cost of 1 tulip = $ 3

6 0

3 years ago

Given the replacement set {2, 3, 4, 5}, solve 4x – 3 = 2x + 5.<br> GIVING 20 POINTS !!

Advocard [28]

Answer:

x=4

Step-by-step explanation:

4x - 3 = 2x + 5

4x - 2x = 5 + 3

2x = 8

x = 8/2

x = 4

7 0

3 years ago

Please help me solve this problem 3x+9 ?

maxonik [38]

Assuming that the expression equals 0

3x+9=0

Subtract 9

3x= -9

-9/3= -3

x= -3

3 0

3 years ago

After 3.5 hours, Patrick had traveled 217 miles. If he travels at a constant speed, how far will he have traveled after 4 hours

Ede4ka [16]

Answer: He would have traveled 248 miles

Explanation: This is a ratio

To find how many miles he would have traveled after 4 hours, we need to apply the information givin into a ration table

(We can put miles on the top and hours on the bottom)

217 ?
------- ------
3.5 4

Now, we can do two things:
1. cross multiply
we would take 217 times 4 (868) and divide that by 3.5 (248)

2. Divide the top and bottom by 3.5 (numerator= 62 denominator= 1)
multiply 62 by 4 to get 248

Hope this helps!

6 0

4 years ago

Without graphing, determine whether the function represents exponential growth or exponential decay.

Vikki [24]

Answer:

Decay.

Step-by-step explanation:

It is decay because .67 is less than 1.

6 0

3 years ago