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RUDIKE [14]
3 years ago
9

Write a brief passage describing a neutral atom of nitrogen-14 (N-14). Describe the number of protons, neutrons, and electrons i

n the atom, where each type of particle is located, and how the terms atomic number, mass number, and atomic mass are related to the particles. Use the periodic table to help you.
Chemistry
2 answers:
Inessa [10]3 years ago
5 0
In nitrogen-14, there are 7 protons, 7 neutrons, and 7 electrons. The protons and neutrons are in the nucleus, and the electrons are in the electron shells. The atomic number is the number of protons, the mass number is the number of protons AND neutrons, and the atomic mass is the average of the masses of all isotopes.
Nevertheless
3 years ago
Your answer should include all the following pieces of information. Check off each of the items you included in your answer. It contains seven protons in the nucleus. It contains seven neutrons in the nucleus. It contains seven electrons in orbitals around the nucleus. Its atomic number is its number of protons. Its atomic mass is the mass of protons and neutrons.
Genrish500 [490]3 years ago
5 0

<u>Answer:</u> This element has 7 protons, 7 electrons and 7 neutrons.

<u>Explanation:</u>

There are 3 subatomic particles present in an atom. They are: protons, electrons and neutrons.

  • <u>Protons:</u> They carry positive charger and are present in nucleus.
  • <u>Electrons:</u> They carry negative charge and are present around the nucleus.
  • <u>Neutrons:</u> They dos not carry any charge and are present in nucleus.

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

Atomic mass is the sum of masses of each isotope each multiplied by their natural fractional abundance. This is also related to protons and neutrons present in an atom.

We are given:

An element having formula _7^{14}\textrm{N}

Atomic number = Number of electrons = Number of protons = 7

Mass number = 14

Number of neutrons = 14 - 7 = 7

Atomic mass of nitrogen = 14.01 amu

Hence, the given element has 7 protons, 7 electrons and 7 neutrons.

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Which of the following are chemicals?<br> clothing<br> food<br> fuels<br> all of the above
Mamont248 [21]

Answer:

i guess fuels are chemicals

6 0
3 years ago
How many grams are there in 7.4x10^23 molecules of Na2SO4?
weeeeeb [17]
Molar mass Na2SO4 = <span>142.04 g/mol

142.04 g -------------- 6.02x10</span>²³ atoms
??  g ------------------ 7.4x10²³ atoms

142.04 x ( 7.4x10²³) / 6.02x10²³

=> 174.60 g
8 0
4 years ago
hydrogen chloride, hydrogen nitrate (v), sodium chloride, sodium hydroxide. Name a substance known as common salt​
trasher [3.6K]

Answer:

C: Sodium chloride

Explanation:

Common salt is gotten when sodium atoms reacts with chlorine atoms in an exothermic reaction to form an ionic substance known as sodium chloride with the chemical formula NaCl.

Equation is;

2Na + Cl2 = 2NaCl

Looking at the options, the correct one is Sodium chloride.

7 0
3 years ago
Which substance is the oxidizing agent in the following reaction? Fe2S3 + 12HNO3 → 2Fe(NO3)3 + 3S + 6NO2 + 6H2O Which substance
aleksandr82 [10.1K]

Answer:

HNO3 is the oxidizing agent

Explanation:

Step 1:

The oxidizing agent is responsible to oxidize another.  but  itself undergoes  a reduction  .

Fe2S3:

Fe has an oxidation number of +3

S has an oxidation number of -2

HNO3:

O has an oxidation number of -2 ( we have 3 times O so this makes -6)

H has an oxidation number of +1

N has an oxidation number of +5

Fe(NO3)3

O has an oxidation number of -2 ( we have 3 times O so this makes -6)

Fe has an oxidation number of +3

Since NO3 has an oxidation number of -1; N has an oxidation number of +5

S alone has an oxidation number of 0

NO2:

O has an oxidation number of -2 (we have 2 times O, this makes -4)

N has an oxidation number of +4

Fe doesn't change from oxidation number. It stays +3

N goes from +5 to +4 → this is a reduction

S goes from -2 to 0 → this is an oxidation

The reducing agent is the compound that contributes the oxidized species (S).

The oxidizing agent contributes the reducing species (N)

The answer is HNO3

5 0
3 years ago
Find the empirical formula of the following compounds:
Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus \frac{mol phosphorus}{ 30.97 g phosphorus}= 0.0293 mol

Moles bromine 6.99 g bromine\frac{mol bromine}{79.90 g bromine}=0.0875 mol

The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

To learn more about empirical formula visit:

brainly.com/question/14044066

#SPJ4

8 0
1 year ago
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