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oksano4ka [1.4K]
4 years ago
10

Please help me thank you :)

Chemistry
2 answers:
LenaWriter [7]4 years ago
5 0

Answer:

D. 3220

Explanation:

1 km equals 1000 m, so 3.22 km is

3220 m

liq [111]4 years ago
4 0
The answer is D.3220
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If 4.65 LL of CO2CO2 gas at 22 ∘C∘C at 793 mmHg mmHg is used, what is the final volume, in liters, of the gas at 35 ∘C∘C and a p
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Answer:

About 7.9 L.

Explanation:

We can utilize the ideal gas law. Recall that:

\displaystyle PV = nRT

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Because the right-hand side stays constant, we have that:
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Hence substitute initial values and known final values:
\displaystyle \begin{aligned} \frac{(793\text{ mm Hg})(4.65 \text{ L})}{(22 \text{ $^\circ$C})} & = \frac{(743 \text{ mm Hg})V_2}{(35\text{ $^\circ$C})} \\ \\ V_2 & = 7.9\text{ L}\end{aligned}

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2.71×10²⁴ particles

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From the question,

If one mole of chlorine contains a particle of  6.02×10²³,

Therefore,

4.5 moles of chlorine will contain a particle of (4.5× 6.02×10²³)

⇒ 27.09×10²³

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