Hoi!
The basic metric unit of capacity is a liter. :)
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
3. A
4.B
5.B
Very happy to help you!
Answer:
y = (-1/2)x + 21/2
Step-by-step explanation:
Given equation:
y - 2x + 7
Coordinates = (5,8)
Find:
Perpendicular equation
Computation:
y = mx + c
y - 2x + 7
y = 2x - 7
So,
m = 2
The negative reciprocal of 2 is -1/2
So,
For,
Coordinates = (5,8)
y = mx + c
8 = (-1/2)(5) + c
8 = -5/2 + c
c = 8 + 5/2
c = 21 /2
So,
y = mx + c
y = (-1/2)x + 21/2
Solve 10x = 4.1 for x. Divide both sides of this equation by 10: x = 4.1 / 10.
x = 0.41
