$r(t)=(\cos{t},\sin{t},t)
\\r'(t)=(-\sin{t},\cos{t},1)
\\t= \frac{3\pi}{6} = \frac{\pi}{2}
\\ r'(t)=(-\sin{\frac{\pi}{2}},\cos{\frac{\pi}{2}},1)
\\ r'(t)=(-1,0,1)
\\
\\x=0+t(-1)=-t
\\y=1+t\times 0=1
\\z= \frac{\pi}{2} +t$

5 0

3 years ago

For f(X)=2x+1 and g(X)=x^2,find (f-g)(X)

Bezzdna [24]

The answer for f(x)-g(x) is $-x^2+2x+1$ .The solution can be obtained by use of concept of functions.

<h3>What is a function?</h3>

A function, in mathematics, can be defined as an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).It useful in mathematical representation of scientific quantities.

We can perform addition and subtraction operations on functions.

The given function f(x) and g(x) are

$f(x)=2x+1\\g(x)=x^2\\f(x)-g(x)=2x+1-x^2\\f(x)-g(x)=-x^2+2x+1$

The solution for f(x)-g(x) is $-x^2+2x+1$ .

To know more about functions visit:

brainly.com/question/12431044

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3 0

1 year ago