Answer:
5 cm
7cm
Step-by-step explanation:
Answer:
Part 1) The area of the circle is 
Part 2) The circumference of the circle is 
Step-by-step explanation:
step 1
The area of a circle is equal to

we have
---> the radius is half the diameter

substitute


step 2
The circumference of a circle is equal to

we have

substitute


Answer:
20
Step-by-step explanation:
Assuming that the equation is x³ = 64, that can be solved by putting cube root on both sides like so: ∛(x³) = ∛64, which simplifies to <em>x = 4</em>.
Plugging that into our expression gives us <em>4² + 4</em>, which is 20.
Answer:
Y=-2/3x + 5
Step-by-step explanation:
For this case we have the following system of two equations with two unknowns:

Adding both equations we have to eliminate the variable "x":

Adding common terms, keeping in mind that different signs are subtracted and the sign of the major is placed:

Answer:

Option A