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nika2105 [10]
2 years ago
10

The expressions that have a value of 180 when b = 4.

Mathematics
1 answer:
klasskru [66]2 years ago
6 0

Answer:

1.  87b−179+957÷87

2. 51b−24

Step-by-step explanation:

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|3k-2|=2|k+2| solve please
djyliett [7]
3k-2=2k+4
-2k. -2k
k-2=4
+2. +2
k =6
4 0
3 years ago
Solve.E6xplain how you get the answer without using a calculator 6/3 + 1/2
fiasKO [112]

I'm just gonna assume that 6/3 and 1/2 are fractions.

First you have to find common denominators for the fractions to be added.

The first common denominator divisible by both the denominators is 6.

So 2x3=6 and 1x3=3

and 3x2+6 and 6x2+12

so that would be 12/6 + 3/6

Then you would proceed to add both of the numerators together which are 12 and 3.

To get a total of 15/6. You can also simplify that into a mixed number 2 1/2.

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Probability is about estimating or calculating how likely or 'probable' something is to happen.
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2 years ago
Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
2 years ago
NEED HELP WILL GIVE BRAINLIEST!
lozanna [386]

Answer: a=60

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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