First, we get ax^2+bx+c. Next, we know that the line of symmetry is -b/2a. Since we know that there is a maximum value, the parabola is facing downwards, so a is negative. For random numbers, we can say that a = -0.5 and b=-10 (b needs to be negative for -b/2a to equal -10), getting -0.5x^2-10x+c. Plugging -10 in for x (since -10 is the middle it is the max), we get -50+100=50. Since the maximum needs to be 5, not 50, we subtract 45 from the answer to get it and therefore make c = -45, getting -0.5x^2-10x-45
Answer:
There are no solutions.
Step-by-step explanation:
If there is 74 and 54 but with the same 15x: there is no solution. Even with negative.
Answer:
No.
Step-by-step explanation:
1. Subsutute p/q with the numbers given, p = -2 and q = 5.
-2 / 5.
2. Divide 2/5 and -2/5 and compare.
2 / 5 = 0.40
-2 / 5 = -0.40
-0.40 < 0.40
If they are not =, then they are <u>NOT</u> equivalent.
Which means, they are Not equivalent.
Answer:
multiply it by zero
Step-by-step explanation:
zero times anything is zero
5x - 20y = 60...reduce by dividing by 5
x - 4y = 12
this is the same as the other equation....therefore, it is the same line...meaning infinite solutions
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y - 7x = -14
y = 7x - 14.....slope = 7, y int = -14
7y - 49x = -2
7y = 49x - 2
y = 7x - 2/7.....slope is 7, y int is -2/7
if the slopes are the same, but the y int are different, then u have a parallel lines with no solutions
