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2 years ago

14

SOMEONE PLSSSS HELP MEEE I WILL. MARK UUUUUU!!

2 answers:

elena55 [62]2 years ago

6 0

It’s all of them :):):):)

luda_lava [24]2 years ago

4 0

Answer:

i think all of them

Step-by-step explanation:

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A business that offers and sells financial services to people is.. A deposit B depository institution C commercial bank D saving

butalik [34]

Answer:

C

Step-by-step explanation:

4 0

3 years ago

I forgot how to do this

adoni [48]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{1}}}}}$

Step-by-step explanation:

$\sf{ \frac{1}{2} \times 2}$

Multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.

$\dashrightarrow{ \sf{ \frac{1 \times 2}{2 \times 1} }}$

$\dashrightarrow{ \sf{ \frac{2}{2} }}$

$\dashrightarrow{ \sf{1}}$

Or, You can simply reduce the fraction with 2, which results to 1.

Hope I helped!

Best regards! :D

6 0

2 years ago

Diego has 150% as much as noahs $5. How much does diego have

pashok25 [27]

Answer: $7.50

Step-by-step explanation:

150% of $5 is $7.50

6 0

2 years ago

Read 2 more answers

Rewrite as a simplified fraction.<br> 2.267....=?

Ugo [173]

Answer:

2267/1000

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Pleases someone explain

Nikolay [14]

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

$\frac{1}{y^{-2}} =\frac{y^2}{1}$ or $y^2$

$2x^{-3}$ or $\frac{2^1x^{-3}}{1} =\frac{2}{x^3}$

$\frac{1}{x^{-5}} =x^5$

When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

$\frac{x^2}{y}$ (can't combine because they have different bases of y and x)

$\frac{x^5}{x^3} =x^{(5-3)}=x^2$

$\frac{2^2}{2} =2^{(2-1)}=2^1 = 2$

When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.

For example:

$(x^2)^3=x^{(2*3)}=x^6$

$(y^2)^{10}=y^{(2*10)}=y^{20}$

$\frac{2e^0}{(e^{-3})^2}$ First multiply the exponents together in the denominator

$\frac{2e^0}{e^{(-3*2)}}= \frac{2e^0}{e^{-6}}$ Now subtract the exponents together

$2e^{(0-(-6))}$ (two negative signs cancel each other out and become positive)

$2e^{(0+6)}$

$2e^6$

7 0

2 years ago