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Musya8 [376]
3 years ago
8

Which of the following mixtures of paint could be used as the missing values in the table ? Choose 2 answers

Mathematics
1 answer:
Kazeer [188]3 years ago
6 0

Answer:

weres the answer how am i going to answer this

Step-by-step explanation:

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∠A and \angle B∠B are supplementary angles. If m\angle A=(x-16)^{\circ}∠A=(x−16) ∘ and m\angle B=(3x+28)^{\circ}∠B=(3x+28) ∘ , t
GalinKa [24]

Answer:

  ∠A = 26°

Step-by-step explanation:

Supplementary angles total 180°.

  ∠A +∠B = 180°

  (x -16)° +(3x +28)° = 180°

  4x° + 12° = 180°

  x° +3° = 45°

  x° = 42°

  ∠A = (x -16)° = 42° -16°

  ∠A = 26°

3 0
3 years ago
Stu Reese has a $150,000 7½% mortgage. His monthly payment is $1,010.10. His first payment will reduce the principal to an outst
BabaBlast [244]

Given that

starting outstanding balance = $150000

rate of interest = 7.5% per year

so rate of interest for 1 month = (7.5/12)% = 0.635%

outstanding balance before 1st monthly payment =  starting outstanding balance   +   0.625% of interest on  starting outstanding balance

= 150000 + (0.625 /100) × 150000

= 150000 + 937.5 = $150937.5

Reduction = outstanding balance after one month - first monthly payment

Reduction  = $150937.5 - 1010.10 = 149927.40

so out of first payment of $1,010.10 ,  $937.5  goes towards interest and remaining $72.6 goes towards reduction of principal that is 150000 - $72.6 = 149927.40.

so correct option is B that is $149927.40.

8 0
3 years ago
500 POINTS PLEASE HELP FASTEST ANSWER WILL BE MARKED BRAINLIEST
diamong [38]

Answer:

Five number summary

Step-by-step explanation:

I just relearned this yesterday

8 0
2 years ago
Read 2 more answers
Evaluate the integral Find the volume of material remaining in a hemisphere of radius 2 after a cylindrical hole ofradius 1 is d
algol13

You want to find the volume inside the hemisphere x^2+y^2+z^2=4 (i.e. inside the sphere but above the plane z=0) and outside the cylinder x^2+y^2=1. Call this region R.

In cylindrical coordinates, we have

\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_1^2\int_0^{\sqrt{4-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta

\displaystyle=2\pi\int_1^2 r\sqrt{4-r^2}\,\mathrm dr

\displaystyle=-\pi\int_3^0\sqrt u\,\mathrm du

(where u=4-r^2)

\displaystyle=\pi\int_0^3\sqrt u\,\mathrm du

=\dfrac{2\pi}3u^{3/2}\bigg|_0^3=2\sqrt3\,\pi

7 0
3 years ago
The perimeter of a rectangular flower garden is 66m and its area is 272m^2. Find the length of the garden.
ExtremeBDS [4]
So we have lengths a and b and are given:

2a+2b = 66 => a+b = 33 => a= 33-b
a*b = 272

plug in one into the other:

(33-b)b = 272 => -b^2 +33b - 272 = 0

Can be factored as (b-16)(b-17) = 0, if you don't "see" this immediately, use the well known abc formula to find b.

So a=16 and b=17 or vice versa.


6 0
2 years ago
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