1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tems11 [23]
4 years ago
7

Two cars having masses in the ratio 4:5, accelerates in the ratio 2:3. Find the ratio of forces exerted by each of them

Physics
1 answer:
katovenus [111]4 years ago
7 0

Answer:

Force=mass×acceleration.

4:5 for masses , 2:3 for acceleration.

For the first car it will be 4×2=8N

For the second car it will be 5×3=15N

You might be interested in
Hey!Can someone solve my question??
Mademuasel [1]

Answer:

P1 = 2680 pa            P2  = 4870pa

T1 = 273k                  T2 = T

From the ideal gas equation,

P1 / T1 = P2 / T2

2680 / 273 = 4870 / T

T = 4870 * 273 / 2860

T  = 496.38 k

Kindly Mark Brainliest, Thanks

4 0
3 years ago
Read 2 more answers
How does under water welding work?
Harrizon [31]

it works by using a really hot substaince to melt something together.

3 0
4 years ago
Read 2 more answers
A vessel containing 200 ml hydrogen gas at pressure 500torr at temperature 10 degree C.Find its volume when pressure increased t
Margaret [11]

Answer:

When the pressure and the temperature are increased the volume is 285.7 ml.

Explanation:

We can find the new volume by using the Ideal Gas Law:

PV = nRT

Where:

P: is the pressure

V: is the volume

n: is the number of moles

R: is the gas constant

T: is the temperature  

Initially, when V₁ = 200 ml, P₁ = 500 torr and T₁ = 10 °C, we have:

nR = \frac{P_{1}V_{1}}{T_{1}}   (1)  

And finally, when P₂ = 700 torr and T₂ = 20 °C, we have:

nR = \frac{P_{2}V_{2}}{T_{2}}   (2)

By equating (1) with (2):

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}                

V_{2} = \frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}} = \frac{500 torr*200 ml*20 ^{\circ} C}{10 ^{\circ} C*700 torr} = 285.7 ml

Therefore, when the pressure and the temperature are increased the volume is 285.7 ml.                                                

I hope it helps you!                  

3 0
3 years ago
I place an ice cube with a mass of 0.223 kg and a temperature of −35◦C is placed into an insulated aluminum container with a mas
Nadya [2.5K]

To solve this problem it is necessary to use the calorimetry principle. From the statement it asks about the remaining ice, that is, to the point where the final temperature is 0 ° C.

We will calculate the melted ice and in the end we will subtract the total initial mass to find out how much mass was left.

The amount of heat transferred is defined by

Q = mc\Delta T

Where,

m = mass

c = Specific heat

\Delta T =Change in temperature

There are two states, the first is that of heat absorbed by that mass 'm' of melted ice and the second is that of heat absorbed by heat from -35 ° C until 0 ° C is reached.

Performing energy balance then we will have to

Q_i-E_h = Q_m

Where,

Q_ i= Heat absorbed by whole ice

Q_m= Heat absorbed by mass

E_h= Heat energy by latent heat fusion/melting

m_i*c_i \Delta T +m*L_f  = (m_wc_w+m_{al}c_{al})\Delta T

Replacing with our values we have that

0.223*2108(-(-35))+m*3.34*10^5 = (0.452*4186+0.553*902)(27-0)

16452.9+334000m = (1892.072+498.806)*27

Rearrange and find m,

m = 0.144Kg

Therefore the Ice left would be

m' = 0.223-0.144

m' = 0.079Kg

Therefore there is 0.079kg ice in the containter when it reaches equilibrium

8 0
3 years ago
A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio
Gnesinka [82]

Answer:

a).a_p=-2.39x10^{-12} rad/s^2

b).t=1016298.8 years

c).T_i=80.58x10^{-3}s

Explanation:

a).

The acceleration for definition is the derive of the velocity so:

a_p=\frac{dw}{dt}

w=\frac{2\pi}{t}

a_p=\frac{dw}{dt}=-\frac{2\pi}{t^2}*\frac{dT}{dt}

dT=0.0808s

dt=1 year*\frac{365d}{1year} \frac{24hr}{1d} \frac{60minute}{1hr} \frac{60s}{1minute}=31.536x10^{6}s

Replacing

a_p=-\frac{2\pi}{0.082s^2}*\frac{9.84x10^{-7}}{31.536x10^{6}s}= -2.39x10^{-12} rad/s^2

b).

If the pulsar will continue to decelerate at this rate, it will  stop rotating at time:

t=\frac{w}{a_p}

w=\frac{2\pi }{t}=\frac{2\pi }{0.0820s}=76.62 rad/s

t=\frac{76.62 rad/s}{2.39x10^{-12}rad/s^2}= 3.2058x10^{13}s

t=1016298.8 years

c).

582 years ago to 2019

1437

T_i=0.0820-9.84x10^{-7}*1437)=80.58x10^{-3}s

5 0
3 years ago
Other questions:
  • [No Value Inputted Into Question]
    10·1 answer
  • An expanded joint surface shaped like a ball and found on the articular end of the epiphysis is called a ______
    12·1 answer
  • A fisherman in a stream 39 cm deep looks downward into the water and sees a rock on the stream bed. How deep does the stream app
    6·1 answer
  • How does the motion of particles in a gas change as the gas cools?
    6·1 answer
  • ____ and ____ both discovered electromagnetic induction. This is that electric current could be produced in a wire by moving a m
    10·1 answer
  • Why shouldn't we consider the needs of humans first
    8·1 answer
  • a sphere of mass 5kg and volume 2×10-5completely immersed in water find the buoyant force exerted water​
    9·1 answer
  • Can someone help me with this
    6·1 answer
  • The r force is the overall force. If two forces are acting in the same direction, the resultant force is the s of all the forces
    6·1 answer
  • If the volume of a container of gas remains constant, what will happen to the pressure of a gas if you increase the temperature?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!