Energy is not created and not destroyed it will only change form
So heres your answer ; It is given off as other forms of energy/light and heat !!
=answer 2nd one
Answer:
Centripetal force is equal to 31.55 N
Explanation:
We have given mass of the body m = 8 kg
Radius of the circular path r = 10 m
It is given that it makes 1 revolution in 10 seconds
Distance traveled in 10 seconds is equal to 
Velocity is equal to 
We have to find the centripetal force
Centripetal force is equal to 
So centripetal force will be equal to 31.55 N
The cart is at rest, so it is in equilibrium and there is no net force acting on it. The only forces acting on the cart are its weight (magnitude <em>w</em>), the normal force (mag. <em>n</em>), and the friction force (maximum mag. <em>f</em> ).
In the horizontal direction, we have
<em>n</em> cos(120º) + <em>f</em> cos(30º) = 0
-1/2 <em>n</em> + √3/2 <em>f</em> = 0
<em>n</em> = √3 <em>f</em>
and in the vertical,
<em>n</em> sin(120º) + <em>f</em> sin(30º) + (-<em>w</em>) = 0
<em>n</em> sin(120º) + <em>f</em> sin(30º) = (50 kg) (9.80 m/s²)
√3/2 <em>n</em> + 1/2 <em>f</em> = 490 N
Substitute <em>n</em> = √3 <em>f</em> and solve for <em>f</em> :
√3/2 (√3 <em>f </em>) + 1/2 <em>f</em> = 490 N
2 <em>f</em> = 490 N
<em>f</em> = 245 N
(pointed up the incline)
Yes, as long as it hasn't reached its maximum speed. Think of a car going 30mph, it can remain at this speed and travel at a constant rate; however, the car could also increase it's speed further. Hope this answers your question.
Answer:
Explanation:
Given
launch velocity 
Launch angle 
Range of Projectile 
Horizontal velocity remain same and only vertical velocity changes.
Initially vertical velocity is in upward direction but as soon as it reaches the ground its direction change but magnitude remain same.
