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oksian1 [2.3K]
3 years ago
7

Help me with problem 8a and b

Mathematics
1 answer:
svetlana [45]3 years ago
8 0

a. The bridge can hold at most 1000 pounds. This tells you everyone's accumulative weight needs to be less than or equal to 1000. The problem does not give your friend's weight... yet. Let x = your friend's weight.

Your friend's weight (x) plus your weight (156) plus everyone else's weight (675) must be less than or equal to (≤) 1000 pounds.

x + 156 + 675 ≤ 1000

Combine like terms (the constants) to simplify and get your final inequality:

x + 831 ≤ 1000

b. Now, we find out your friend weighs 182 pounds. x = 182. We plug this into the above equation. If it results in a true statement, then you both can walk across the bridge.

182 + 831 ≤ 1000

1013 ≤ 1000, is not a true statement.

No. You both cannot walk across the bridge as is because the weight of the people on the bridge would be 13 pounds over the weight limit.

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Translate this verbal expression into an algebraic equation and solve: thirteen less than twice the sum of a number and six is 4
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Answer:

Please check the explanation.

Step-by-step explanation:

Given the verbal expression

''Thirteen less than twice the sum of a number and six is 47''.

Let us break down the verbal expression into an algebraic equation

  • Let the number be = n
  • Twice the number n = 2n
  • Sum of twice the number and six = 2n+6
  • Thirteen less than twice the sum of a number and six = 2n+6-13

And finally

Thirteen less than twice the sum of a number and six is 47:

2n+6-13 = 47

Therefore, the equation is:2n+6-13 = 47

Solving the algebraic expression

solving the equation for 'n'

2n+6-13 = 47

2n-7=47

Add 7 to both sides

2n-7+7=47+7

Simplify

2n=54

Divide both sides by 2

\frac{2n}{2}=\frac{54}{2}

Simplify

n=27

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