1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tju [1.3M]
3 years ago
6

15y+31=61 how do I solve this

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0
15y + 31 = 61
15y = 61 - 31
15y = 30
y = 30 ÷ 15
<u>y = 2</u>
You might be interested in
Yvonne is thinking of a number. fifty, decreased by three times the the number, is the same as seven times the number, increased
Lady_Fox [76]
3x-50=7x+80
I think this is correct! Hope I helped!
4 0
3 years ago
luis makes a 4% commision on his sales in a sporting goods store. For a $70 purchase, how much commision does Luis earn?
Fiesta28 [93]
He made $2.80 because if you multiply 70 by .04 it’s 2.8
4 0
2 years ago
Which unit rate corresponds to the proportional relationship shown in the graph?
Evgen [1.6K]

Answer:

1.5 cm/s​

Step-by-step explanation:

The unit rate is the same as the slope.

To find the slope, we use the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

Using our points, we have

m = (9-0)/(6-0) = 9/6 = 3/2 = 1.5 cm/s

6 0
3 years ago
Read 2 more answers
Miss lead says that if y varies directly with x and y=15 when x=-3, then y=-20 when x=4. Is she correct? Answer in complete sent
gizmo_the_mogwai [7]

Answer:

Yes,  she is correct.

Step-by-step explanation:

y = kx   is direct variation

15 = k*-3

k = -5.

So the equation of variation is

y = -5x

When x = -4:

y -5*-4 = 20.

6 0
2 years ago
a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
Doss [256]

Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

Total time taken in 2003- total time taken in 2005

=2\frac{17}{24}-\frac{3}{8}

\frac{48+17}{24}-\frac{3}{8}

=\frac{65}{24}-\frac{3}{8}

=\frac{65-9}{24}

=\frac{56}{24}

\frac{7}{3}

=2\frac{1}{3} minutes


3 0
3 years ago
Read 2 more answers
Other questions:
  • Find the value of 24ft and 9ft
    5·1 answer
  • Rewrite the function f(x)=7 (1/2)^3x using the properties of exponents.
    10·1 answer
  • What is 3/4 of the product of 2/4 and 6/8?​
    5·1 answer
  • I need help with #10 please
    11·1 answer
  • I need to find the zeros of the function, please
    8·1 answer
  • In which set do all values make the inequality 3x+5&lt;26 true?
    10·1 answer
  • Which expression has a value of 1 when x = 2.
    8·1 answer
  • Pls hurrryyyy math test
    12·1 answer
  • How many solutions can be found for the equation 4x 5 = 10? Zero One Two Infinitely Many.
    12·1 answer
  • Lillian has a bag that contains pineapple chews, cherry chews, and peach chews. She
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!