Question

(9.2×10^5)(4×10^-3)​

Answer 1

first change the 9.2 to standard form. which is

$92 \times {10}^{ - 1}$

now the whole equation becomes

$(92 \times {10}^{ - 1} \times {10}^{ - 5} ) \times (4 \times {10}^{ - 3} )$

$= 92 \times 4 \times {10}^{ - 1 + 5 - 3}$

$= 368 \times {10}^{1}$

$= 3.68 \times {10}^{2 + 1}$

$= 3.68 \times {10}^{3}$