-6z+ 12
= -6(z -2) (distributive property)
The final answer is -6(z -2)~
Answer:
-16
Step-by-step explanation:
Horizontal Shrink: y = cos 2x or if the coefficient of x is greater than 1
Vertical Stretch: y = 2 cos x or if the coefficient if cos x is greater than 1
Horizontal Stretch: y = cos (1/2) x or if the coefficient of x is less than 1
Vertical Shrink: y = (1/2) cos x or the coefficient of cos x is less than 1
The base value is 1 since it is the original coefficient of x and cos x. The values would adjust depending on the original coefficients.
Answer: B) y=6/11.
To find the horizontal asymptote(s) you must find the limit as x approaches infinity and the limit as x approaches -infinity.
Using L’Hôpital’s rule:
lim x-> infinity (f(x))=6/11.
lim x-> -infinity (f(x))=6/11.
