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3 years ago

Simplify 28y=12x+84I don't know this

Mathematics

1 answer:

irina1246 [14]3 years ago

7 0

Divide everything by 4 getting:
7y=3x+21
then get all of the variables on one side by subtracting 3x:
7y-3x=21

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I Will give out brainliest help ASAP

kirza4 [7]

Step-by-step explanation:

f(x) = 2x² + 9

f(5) = 2(5)² + 9

= 2(25) + 9

= 50 + 9

= 59

6 0

3 years ago

Find gradient xe^y + 4 ln y = x² at (1, 1)

cricket20 [7]

$xe^y+4\ln y=x^2$

Differentiate both sides with respect to x, assuming y = y(x).

$\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}$

$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

Solve for dy/dx :

$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}$

If y ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}$

4 0

3 years ago

Juan is making a scale model of the Statue of Liberty. He is given the choice of using either of these scales 1:100 or 1:1000. W

DIA [1.3K]

Answer:1:1000

Step-by-step explanation:

It’s 1:1000 because compared to the other one the height of the model would be 9.3 centimeters if 1:1000 was the scale of the model

8 0

3 years ago

Read 2 more answers

What is the equation, in point-slope form, for a line that goes through (8, −4) and has a slope of −5/6 ?

horrorfan [7]

Point-slope form, y-y1 = m(x-x1)

(y-(-4)) = -5/6 (x-8)

y+4 = -5x/6+20/3

y = -5x/6+20/3 - 4

y = -5x/6 + 8/3

6 0

3 years ago

Read 2 more answers

Find the point-slope equation for the line that passes through the points (5, 35) and (-6, -31). Use the first point in your equ

AleksandrR [38]

Answer:

Maya, this is such a common question on here, so i'm very interested in what's difficult about this problem for you. Please comment about this. Below is the answer and how to find it.

Step-by-step explanation:

point P1 (5,35) in the form (x1,y1)

point P2(-6,-31) in the form (x2,y2)

slope = m

m = (y2-y1) / (x2-x1)

m = (-31-35) / (-6-5)

m = -66 / -11

they made it easy for you , huh

m = 6

use point / slope fomula, y-y1 = m(x-x1) and plug in one point, either would work, since i've already labeled it with point P1, let's use that point

y-35 = 6(x-5)

y-35 = 6x-30

y = 6x - 30 + 35

y = 6x + 5

Maya, this really is a very common question on here, I really am curious about what's tricky in the problem for you and many many others. please let me know in comments section, thanks MMM

8 0

2 years ago

Read 2 more answers