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3 years ago

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Javed is building a birdhouse in the shape of a triangular pyramid. He drew the net for his birdhouse and labeled the dimensions

. The base is an isosceles triangle with two side lengths of 20 cm.
How much wood will Javed need for the birdhouse?

_____square centimeters

1 answer:

professor190 [17]3 years ago

5 0

Answer:

884

Step-by-step explanation:

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I need help please it’s due tomorrow.......

Sholpan [36]

Let
x-------> the width of the rectangular area
y------> the length of the rectangular area

we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2

substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft

see the attached figure
the solution is<span> the shaded area</span>

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3 years ago

Draw or write two ways to use a doubles fact to find 6+7

PtichkaEL [24]

Here are a few doubles facts:

5+5=10
2+2=4
3+3=6

A double is simply a pair of identical numbers added together. There's a pair of doubles you can <em>subtract </em>1 from to get 6+7, and there's a pair you can <em>add</em> 1 to get the same answer. What are those pairs?

Hint: If you take the example 3+4, you can either <em>subtract 1</em> from the double 4+4 or <em>add 1</em> to the double 3+3 to obtain your answer.

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3 years ago

Help please! Will pick the Brainliest.<br> (sorry if it’s sideways)

KatRina [158]

1.

$(x^2y^8)^\frac{2}{3}=x^{2\cdot\frac{2}{3}}y^{8\cdot\frac{2}{3}}=x^{\frac{4}{3}}y^{\frac{16}{3}}=x^{1\frac{1}{3}}y^{5\frac{1}{3}}=x^1x^\frac{1}{3}y^5y^\frac{1}{3}=xy^5\sqrt[3]{x}\sqrt[3]{y}=\boxed{xy^5\sqrt[3]{xy}}$

Answer B)

2.

$\frac{1}{3}\left(\frac{2}{15}x-\frac{2}{3}\right)>x+\frac{1}{5}\quad|\cdot3\\\\\\\frac{2}{15}x-\frac{2}{3}>3x+\frac{3}{5}\quad|\cdot15\\\\\\2x-\frac{30}{3}>45x+\frac{45}{5}\\\\2x-10>45x+9\\\\-10-9>45x-2x\\\\-19>43x\quad|:43\\\\\boxed{x$

Answer B)

3.

$\sqrt{14xy}\cdot\sqrt{12}\cdot\sqrt{30y}=\sqrt{14\cdot12\cdot30}\cdot\sqrt{xy^2}=\sqrt{2\cdot7\cdot3\cdot4\cdot2\cdot3\cdot5}\cdot\sqrt{xy^2}=\\\\=\sqrt{2^2\cdot3^2\cdot2^2\cdot5\cdot7}\cdot\sqrt{xy^2}=2\cdot3\cdot2\cdot\sqrt{35}\cdot y\cdot\sqrt{x}=\boxed{12y\sqrt{35x}}$

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4 years ago

Which equation has a y intercept of 2 and a slope of 1/2?

Strike441 [17]

The second one is the answer.
y=mx+b
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4 years ago

Starting at time t = 0, the altitude of one helicopter is given by A1 = 600 + 150t, and the altitude of a second helicopter is g

Soloha48 [4]

Answer:

The equation for difference in altitude of the two helicopters is A = 650 - 100t

Step-by-step explanation:

Given;

The altitude of one helicopter is, A1 = 600 + 150t

The altitude of a second helicopter is, A2 = 1250 + 50t

Their difference in altitude, A at time t, is calculated as

A₂ - A₁ = A = (1250 + 50t) - (600 + 150t)

A₂ - A₁ = A = 1250 + 50t - 600 -150t

A₂ - A₁ = A = 1250 - 600 + 50t - 150t

A₂ - A₁ = A = 650 - 100t

Therefore, the equation for difference in altitude of the two helicopters is A = 650 - 100t

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3 years ago