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Anton [14]
4 years ago
12

forty years ago gasoline cost $0.30 per gallon on average. ten years ago gasoline average about $1.50 per gallon. What is the pe

rcent increase in cost of gasoline?
Mathematics
1 answer:
DiKsa [7]4 years ago
3 0
It is as 5x's as much.
<em>$0.30 X 5 = $1.50</em>
Hope I helped
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Any help??please????
Leona [35]
The answer is C. it is C because if the numerator is 0, the answer ALWAYS comes to be 0.
4 0
3 years ago
Read 2 more answers
Abby is going to ride her bike to her friend's house that lives 6 miles away. She can ride her bike at a rate of 2 miles per hou
Volgvan

Answer:

To travel half a distance Abby requires 1.5 hrs.

Step-by-step explanation:

Given:

Abby is going to ride her bike to her friend's house that lives 6 miles away.

Distance = 6 miles

She can ride her bike at a rate of 2 miles per hour.

Speed = 2 miles per hour

We need to find the time required to ride her bike half of the distance.

Now Distance = \frac{6}{2} =3 \ miles

Now Time required can be calculated by Dividing distance with speed.

Time (hours) = \frac{3}{2}=1.5 \ hrs

Hence To travel half a distance Abby requires 1.5 hrs.

4 0
3 years ago
Maria walks at a rate of 3 meters per second on a moving walkway traveling at a speed of 1 meter per second in the opposite dire
vichka [17]
When you set up equations like this, look at the units for help. They cancel out during division and multiplication like numbers to give desired quantities. Rates can be reversed if need be (3 meters/sec or 1/3 sec/meter).

time × (distance / time) = distance
See.. time/time = 1;  leaving distance

Subtract the rate of the opposing walkway...
t × (3 m/s - 1 m/s) = d
2t = d

Answer is then A.
4 0
3 years ago
Simplify the following expression 3x(x^2-5x+6)
Natalka [10]
3x^3-15x^2+18x hope it helps :-)
8 0
3 years ago
Stuck, help please !
Olin [163]

Use the fundamental trigonometric equation

\sin^2(x) + \cos^2(x) = 1 \implies \sin^2(x) = 1-\cos^2(x)

To rewrite the equation as

1-\cos^2(x) = 1-\cos(x)

Subtract 1 from both sides:

-\cos^2(x) = -\cos(x)

Add \cos^2(x) to both sides:

\cos^2(x) - \cos(x) = 0 \iff \cos(x)\left(\cos(x)-1\right)=0

A multipication is zero if and only if one of the factors is zero. So, the solutions are given by

\cos(x)=0 \iff x=\dfrac{\pi}{2}+k\pi,\quad k \in \mathbb{Z}

or

\cos(x)-1=0 \iff \cos(x)=1 \iff x=2k\pi,\quad k \in \mathbb{Z}

5 0
4 years ago
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