Question

Find the equation of a line that runs through

Answer 1

Answer:

The equation of a line that runs through  (-6,2) and is parallel to a line with a slope of (-1/4)     is  x + 4y  - 2 = 0

Step-by-step explanation:

Slope of the parallel  equation is m 1 = (-1/4)

If the two liner are parallel the, slope of both lines are equal.

⇒The slope of the equation of line = m2  = m1  = -(1/4)

The point (x0, y0)  = (-6,2)

Now, by THE POINT SLOPE FORMULA:  The equation of a line is given as

( y - y0)  =  m (x -x0)

Now, here the equation of line is given as:

$y - 2 = (\frac{-1}{4}) (x - (-6)) \implies 4(y-2) = -1(x + 6)$

or, 4y - 8 + x + 6 = 0

or, x + 4y  - 2 = 0

Hence, the required line equation is  x + 4y  - 2 = 0