"13" or "more than 13" rides will make the weekly unlimited pass more cost effective. A further solution is provided below.
The given values are:
- Base fare per ride = $2.75
- Discount = 5%
- Weekly unlimited Metro Card costs = $32
The Fare after discount will be:
= 
= 
= 
= 
($)
hence,
In $32, the minimum number of rides will be:
= 
= 
or,
= 13
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Answer:
The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2
0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2
V = ∫∫∫ dzdydx
dz has changed from zero to 12−3y^2
dy has changed from zero to 2-x
dx has changed from zero to 2
V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =
24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20
Step-by-step explanation:
Answer:
a) 7/10
b) 1/6
Step-by-step explanation:
a) There are 10 ways to roll a 5 or less. Of those, 7 are greater than 3.
(die 1)(die 2) ∈ {11, 12, 21, 13, 22, 31, 14, 23, 32, 41}
p(>3 | ≤5) = 7/10
__
b) Of the 36 possible outcomes of rolling two dice, there are 6 ways to have a 6 and an odd number:
{16, 36, 56, 61, 63, 65}
The probability of interest is 6/36 = 1/6.
Answer:
Yes, it does
Step-by-step explanation:
Ab+ac=a(b+c)
a is common factor
factor
6ab=2*3*a*b
9bc=3*3*b*c
common factor is 3*b or 3b
3b(2a)+3b(3c)=3b(2a+3c)
