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Liono4ka [1.6K]
3 years ago
7

Ma= P2-P1/t solve for p1​

Mathematics
1 answer:
natulia [17]3 years ago
3 0

Answer:

P1 =  P2 - ma*t

Step-by-step explanation:

ma= P2-P1/t

we multiply by t both sides of the equation

ma*t = (P2 - P1)*t/t

ma*t = P2 - P1

we sum by P1 both sides of the equation:

P1 +ma*t = P2 - P1 +P1

We ave:

P1 + ma*t = P2

we subtract by ma*t both sides of the equation:

P1 + ma*t -ma*t = P2 - ma*t

finally we have:

P1 =  P2 - ma*t

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Kathi and Robert Hawn had a pottery stand at the annual Skippack Craft Fair. They sold some of their pottery at the original pri
Vinil7 [7]

Answer:

The number sold at $12.50 is  25

The number sold at $9.50 is 62

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations:

x 12.50 + y 9.50=901.50

x+y= 87

Where

x= number of pottery pieces sold

y= number of pottery pieces sold at a decreased price  

Multiplying the second equation by 9.50, and subtracting the second equation to the first equation:

12.50 x + 9.50y = 901.50

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9.50 x+ 9.50 y= 826.5

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3 x = 75

Solving for x

x =75/3

x = 25

Replacing x=25 on any equation:

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25+y =87

y=87-25

y= 62

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4 years ago
Write an equation for the n term of the arithmetic sequence shown below, then find the
marysya [2.9K]

Step-by-step explanation:

Tn= a+(n-1)d

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6 0
3 years ago
Find the area of the shaded region
Alex777 [14]

∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.

Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².

∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find

\sin(30^\circ) = \dfrac{h}{4\,\rm cm} \implies h= 2\,\rm cm

where h is the length of the altitude originating from vertex O, and so

\left(\dfrac b2\right)^2 + h^2 = (4\,\mathrm{cm})^2 \implies b = 4\sqrt3 \,\rm cm

where b is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².

So, the total area of the shaded region is

(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²

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2 years ago
HFG would equal what degrees?
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Answer:

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3 years ago
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Answer:

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Step-by-step explanation:

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