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2 years ago

Which piece of personal information do websites often require users to enter?

Computers and Technology

2 answers:

andrey2020 [161]2 years ago

8 0

The most common type of information that a website will ask you for is a password, which is unique to that site.

Eye color is irrelevant for sites since there are only about 5 possible colors for human eyes. Most of the time there is no practical use for that information.

Location is mostly irrelevant since your location can change when you visit a site. If it is asking you for it, it's mostly for a special feature unique to that site.

Name is a close answer, but not all websites will ask you for your actual name. Instead, they will ask you for a custum username instead which is different.

rodikova [14]2 years ago

6 0

Answer:

the answer is password

Explanation:

You might be interested in

Individuals and businesses have concerns about data security while using Internet-based applications. Which security risk refers

Katen [24]

Answer:

Spam

Explanation:

If you receive in bulk the unsolicited messages, then that does mean that your inbox is being spammed. This will not harm you but you will lose the Gb that is allocated to your mailbox. And if you will not check then your mailbox will soon be full, and you might not receive some of the important messages that you should reply to immediately.

6 0

2 years ago

G The method of mapping where each memory locationis mapped to exactly one location in the cache is

Otrada [13]

Answer:

Direct Mapped Cache

Explanation:

Given that a Direct Mapped Cache is a form of mapping whereby each main memory address is mapped into precisely one cache block.

It is considered cheaper compared to the associative method of cache mapping, and it is faster when searching through it. This is because it utilizes a tag field only.

Hence, The method of mapping where each memory location is mapped to exactly one location in the cache is "Direct Mapped Cache"

4 0

2 years ago

Based on the information in the table, which of the following tasks is likely to take the longest amount of time when scaled up

kakasveta [241]

Answer:

Task A

Explanation:

8 0

2 years ago

The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices

erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;

import java.util.Arrays;

public class Main {

public static void main(String args[]) {

Scanner input = new Scanner(System.in);

int row, col;

System.out.print("Rows: "); row = input.nextInt();

System.out.print("Cols: "); col = input.nextInt();

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}

public static int[] findmax(int[][] Array2D,int row, int col) {

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i;

maxitem[1] = j; } } }

return maxitem;

}

Explanation:

The next two lines import the scanner and array libraries

import java.util.Scanner;

import java.util.Arrays;

The class of the program

public class Main {

The main method begins here

public static void main(String args[]) {

The scanner function is called in the program

Scanner input = new Scanner(System.in);

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input

System.out.print("Rows: "); row = input.nextInt();

This next instructions prompt the user for columns and get the column input

System.out.print("Cols: "); col = input.nextInt();

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

This calls the findmax function. The returned array of the function is saved in maxarray

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col) {

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i; -- The row position is saved in index 0

maxitem[1] = j; -- The column position is saved in index 1} } }

This returns the 1 d array

return maxitem;

}

7 0

2 years ago

How come the scroll bar on the PA emojis only appears sometimes? how do I make it appear?

astraxan [27]

Answer it your own self everybody can't always give u the answers

5 0

2 years ago