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Ivahew [28]
3 years ago
5

Find the distance between the points with the given coordinates (-2, -5) and (-2, 4).

Mathematics
1 answer:
bija089 [108]3 years ago
6 0
I hope this helps you

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Is -15 an integer and rational number?​
WARRIOR [948]

Answer:

I guess it would help you

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2 years ago
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Round 64509.6429226 to 2 decimal places.
pychu [463]

Answer:

64509.64

Step-by-step explanation:

Don't worry about what's after two decimal places, unless the number in the thousandths place is 5 or higher.

8 0
3 years ago
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What is the length of u and v in this 30-60-90 triangle
qwelly [4]

Answer:

option 2

Step-by-step explanation:

Using trigonometric ratio:

Cos \ 60 = \frac{adjacent } {hypotenuse}  \\\\\frac{1}{2} = \frac{4}{u}\\\\1 \times u = 2 \times 4 \\\\u = 8

Now using Pythagoras theorem we will find v

8^2 = 4^2 + v^2\\\\64 = 16 + v^2\\\\v^2 = 64 - 16 \\\\v = \sqrt{48} = \sqrt{16 \times 3}  = \sqrt{4^2 \times 3 }  = 4\sqrt{3}

8 0
2 years ago
A photographer charges a sitting fee of $15 plus $3 for each pose. Write a function to describe the situation. Find a reasonable
Diano4ka-milaya [45]

Answer:y=3x+15

Step-by-step explanation: (1,18), (2,21), (3,24), (4,27), (5,30) domain is your x values 1,2,3,4,5. Range is your y values. I’d assume someone wouldn’t pay $15 for 0 poses.

6 0
2 years ago
Justin packed two suitcases for his trip and compared the weights of the items he packed in each of the suitcases. A number line
BabaBlast [244]

Answer:

The correct option is;

The data for suitcase 1 have an outlier but the data for suitcase 2 does not

Step-by-step explanation:

Range of a box plot

Interquartile range (IQR) for bot suitcases we have

Here we have for suitcase 1

IQR = Q₃ - Q₁ = 12 - 8 = 4

For suitcase 2

IQR = Q₃ - Q₁ = 18 - 5 = 13

Lower outlier = Q₁ - 1.5×IQR

Higher outlier = Q₃ + 1.5×IQR

For suitcase 1 we have;

Lower outlier = 8 - 1.5×4 = 2 (No lower outlier)

Higher outlier = 12 + 1.5×4 = 18

Hence, whereby the whiskers range from 4 to 30, suitcase 1 has a higher outlier

For suitcase 2 we have;

Lower outlier = 5 - 1.5×13 = -14.5  (No lower outlier)

Higher outlier = 18 + 1.5×13 = 37.5

Hence, whereby the whiskers range from 2 to 20, suitcase 2 has no outlier.

Therefore, the correct option is the data for suitcase 1 have an outlier but the data for suitcase 2 does not.

4 0
3 years ago
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