Answer: 1,285, 1,282, 1,278
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Has the correct y-axis and has the graph going the correct way for both functions.
Taking the derivative of 7 times secant of x^3:
We take out 7 as a constant focus on secant (x^3)
To take the derivative, we use the chain rule, taking the derivative of the inside, bringing it out, and then the derivative of the original function. For example:
The derivative of x^3 is 3x^2, and the derivative of secant is tan(x) and sec(x).
Knowing this: secant (x^3) becomes tan(x^3) * sec(x^3) * 3x^2. We transform tan(x^3) into sin(x^3)/cos(x^3) since tan(x) = sin(x)/cos(x). Then secant(x^3) becomes 1/cos(x^3) since the secant is the reciprocal of the cosine.
We then multiply everything together to simplify:
sin(x^3) * 3x^2/ cos(x^3) * cos(x^3) becomes
3x^2 * sin(x^3)/(cos(x^3))^2
and multiplying the constant 7 from the beginning:
7 * 3x^2 = 21x^2, so...
our derivative is 21x^2 * sin(x^3)/(cos(x^3))^2
60% is 0.60 so you do 0.60 x 29 which = to 17.4
so your answer is 17.40 or 17.4 is 60% of 29
Suppose that the farmer had bought the rice at x dollars per bag and had sold them at a 25% markup. How much did the bags cost him before he added the markup? 1.25x =$75 results in $75/1.25, or $60 per bag.
If he sold 25 bags, his profit would be 1.25($60/bag)(25 bags) = $1875.
I very seriously doubt that the rice was $7500 per bag. Perhaps you meant $75/bag...?
