Its y=mx+b so you will get b as the answer
Answer:
a) 4/27
b) 1/3
c) 6/27
Step-by-step explanation:
HI!
a)
The event A has only one member:
T T H
Therefore:
P(A) = P(T)P(T)P(H) = (2/3)(2/3)(1/3) = 4/27
b)
For event B, we are only interested in the last toss
x x H
Since the first two tosses are not important for event B they do not contribute to P(B)
P(B) = 1 * 1* P(H) = 1/3
c)
The following are elements of C:
H H T
H T H
T H H
Therefore:
P(C) = P(HHT) + P(HTH) + P(THH)
We can easily see that the probability of the three members is the sam:
P(HHT) = (1/3) (1/3) (2/3) = 2/27
P(HTH) = (1/3) (2/3) (1/3) = 2/27
P(THH) = (2/3) (1/3) (2/3) = 2/27
Therefore:
P(C) = 3 P(HHT) = 6/27
Express x from first equation:
x = y - z - 1
Replace x with found value in second equation and solve it:
y - z - 1 + y + z = 5
2y - 1 = 5
2y = 6
y = 3
Replace x with found value in third equation:
y - z - 1 + y - z = -3
Replace y with found value in this equation and solve it:
3 - z -1 + 3 - z = -3
-2z = -3 - 3 + 1 - 3
-2z = -8
2z = 8
z = 4
Find x by replacing y and z in first equation and solving it:
x = y - z - 1
x = 3 - 4 - 1 = -2
So x = -2, y = 3, z = 4
Answer:
Y= 12.5+X
Step-by-step explanation:
Y=43.75
X=1.25x25=31.25
so 43.75 minus 31.25= 12.5
he spent 12.5 on fair addmition