Ask question

Ask question

All categories

3 years ago

7

A person weighing 170 lb would burn A person weighing 170 lb burns 8.6 calories per minute while mowing a lawn. How many calorie

s would be burned in 9 hr of mowing?

1 answer:

daser333 [38]3 years ago

4 0

They would lose 4,644 calories

You might be interested in

Pyramid A is a square pyramid with a base side length of 7 inches and a height of 6 inches. Pyramid B has a volume of 3,136 in3.

julia-pushkina [17]

The answer is B.
V=(7) (7) (6) / 3
V=98 in 3
3136/98=32

8 0

2 years ago

Ksivusya [100]

Answer:

I got 2x^3+3x^2-4x-12

Step-by-step explanation:

I hope this helps a little bit

3 0

1 year ago

For which values of P and Q does the following equation have infinitely many solutions ?

Rzqust [24]

I’d say the answer would be d

7 0

3 years ago

What is 3/18 and 12/20 simplified

grin007 [14]

3/18= 1/6

12/20= 3/5

5 0

3 years ago

Read 2 more answers

Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125

liq [111]

For the given equation;

$(3x-5)^2=-125$

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

$\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}$

Now that we have expanded the left side of the equation, we would have;

$\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}$

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}$

ANSWER:

$x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}$

3 0

6 months ago