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BlackZzzverrR [31]
3 years ago
10

the soccer club is selling tshirts and washing cars to raise money for a summer trip. last week, the club raised $292.50 by sell

ing 15 tshirts and washing 12 cars. this week, it raised $747.50 by selling 45 tshirts and washing 10 cars
Mathematics
1 answer:
Delvig [45]3 years ago
6 0

The equation can be made by:

Letting x be the price of each tshirt sold

Y be the cost of washing cars

So the equation 1:

292.50 = 15x + 12y

Then the equation 2 is for this week:

<span>747.50 = 45x + 10y</span>

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Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
3 years ago
Find the area of each sector shown (the shaded section)
mihalych1998 [28]

Answer:

The area of the sector (shaded section) is 29.51 m^{2}.

Step-by-step explanation:

Area of a sector = (θ ÷ 360) \pir^{2}

where θ is the central angle of the sector, and r is the radius of the circle.

From the diagram give, diameter of the circle is 26 m. So that;

r = \frac{diameter}{2}

 = \frac{26}{2} = 13 m

θ = 360 - (180 + 160)

  = 360 - 340

  = 20^{o}

Thus,

area of the given sector = \frac{20}{360} x \frac{22}{7} x (13)^{2}

                                        = \frac{20}{360} x x \frac{22}{7} x 169

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The area of the sector (shaded section) is 29.51 m^{2}.

4 0
3 years ago
How do I solve this problem?
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Next time use the desmos calculator online and input the numbers.

The answer to this equation is:

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3 years ago
What's the greatest common factor between 324 and 63
Klio2033 [76]

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Step-by-step explanation:

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Students at a virtual school are allowed to sign up for one math class each year. The numbers of students signing up for various
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A well formatted table of the distribution is attached below :

Answer:

0.124

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3.) P(Algebra 11 | 11th grade) = P(Algebara11 n 11th grade) / P(11th grade) = 100 / 245 = 0.408

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