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2 years ago

The product of x and 7 is at least 21

Mathematics

2 answers:

Natali [406]2 years ago

8 0

It’ll be 3

7 x 3 = 21

avanturin [10]2 years ago

4 0

3 or greater. You could replace x with any number greater than 3, and your product would be at least 21. I hope this helps :)

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Vedmedyk [2.9K]

Huh come again? I’m not sure what you just said

6 0

2 years ago

Write an expression. That is the equivalent to 3/5 (3y + 15)

OlgaM077 [116]

9y/5 +5

Im sorry dont have an expression but i hope i got it right

4 0

2 years ago

Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.

dsp73

Answer:

The required sequence is $a_n=20(\frac{1}{2})^{n-1}$ . The average rate of change from n = 1 to n = 3 is -7.5.

Step-by-step explanation:

From the given graph it is clear that the sequence is a GP because the all terms are half of their previous terms.

Here, $a_2=10,a_3=5,a_4=2.5,a_5=1.25$

$r=\frac{a_3}{a_2}=\frac{5}{10}=\frac{1}{2}$

The common ratio of GP is 1/2.

$r=\frac{a_2}{a_1}$

$\frac{1}{2}=\frac{10}{a_1}$

$a_1=20$

The first term of the sequence is 20.

The formula for sequence is

$a_n=a(r)^{n-1}$

Where a is first term and r is common difference.

The required sequence is

$a_n=20(\frac{1}{2})^{n-1}$

The formula for rate of change is

$m=\frac{f(x_2)-f(x_1)}{x_2-x_1}$

The average rate of change from n = 1 to n = 3 is

$m=\frac{f(3)-f(1)}{3-1}$

$m=\frac{5-20}{3-1}$

$m=\frac{-15}{2}=-7.5$

Therefore the required sequence is $a_n=20(\frac{1}{2})^{n-1}$ . The average rate of change from n = 1 to n = 3 is -7.5.

8 0

3 years ago

Read 2 more answers

Can someone answer this plz (-2z^2-14)-(-12z^2)

Orlov [11]

Answer:

$\large\boxed{(-2z^2-14)-(-12z^2)=10z^2-14}$

Step-by-step explanation:

$(-2z^2-14)-(-12z^2)=-2z^2-14+12z^2\qquad\text{combine like terms}\\\\=(-2z^2+12z^2)-14=10z^2-14$

8 0

3 years ago

Write a verbal statement that represents the expression 4 + k.

jolli1 [7]

The sum of four and a number

7 0

3 years ago

Read 2 more answers