7, 13, 19 and 25 have a common difference: 6.
6 added to 7 gives us 13; 6 added to 13 gives us 19, and so on.
Explicit formula: a(n) = 7 + 6(n-1), where 7 is the first term and n is the counter (1, 2, 3, ...).
The first term is 7 (given). This corresponds to n=1.
The second term is a(2) = 7 + 6(2-1), or 7 + 6, or 13. This corresponds to n = 2.
and so on.
=(-5 x 4 x 1)^-2
= (-20)^-2
= 1/(-20)^2
= 1/400
so D then i think
3(5y-6)-2y=8
15y-18-2y=8
13y-18=8
13y=26
y=2
That is because you have the expression you can substitute it on the system.( hope this helps)
Step-by-step explanation:
A =nr²
=3.14 × (80/2)
=3.14 × 40
= 125.6yd²
