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Anna007 [38]
4 years ago
11

Will give brainliest! and EXTRA points.

Mathematics
1 answer:
denis23 [38]4 years ago
3 0

How far did the frog jump? the answer is one of the solutions of the quadratic equation

0= -0.017x^2+0.51x

because that's where the frogs height is 0 (y=0) feet.

Use your favorite formula for quadratic equations. I got two solutions: 0 and 30. 0 is clearly the starting point and 30 feet is point where the frog lands.

The height is the maximum of the quadratic form. Use the formula for maximum x of a quadratic: xmax = -b/(2a) = -0.51/(2*0.017) = 15. The maximum at that point is ymax = 3.825

So, the correct answer is (a) 30 ft far and 3.83 high.

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A student bought 84 pencils. If he sharpened 35 pencils, what is the ratio of the unsharpened pencils to the sharpened pencils?
Dima020 [189]
Number of pencils bough by the student = 84
Number of pencils sharpened by the student = 35
Then
The number of pencils that was not sharpened = (84 - 35)
                                                                             = 49
So 35 pencils have been sharpened and 49 pencils have not been sharpened.
Then Number of pencils unsharpened:Number of pencils sharpened = 49:35
                                                                                                               = 7:5
So the ratio of the number of unsharpened pencil to the number of sharpened pencil is 7:5
6 0
4 years ago
A sample of 900900 computer chips revealed that 49%49% of the chips do not fail in the first 10001000 hours of their use. The co
dedylja [7]

Answer:

The proportion of chips that do not fail in the first 1000 hours of their use is 52%.

Step-by-step explanation:

The claim made by the company is that 52% of the chips do not fail in the first 1000 hours of their use.

A quality control manager wants to test the claim.

A one-proportion <em>z</em>-test can be used to determine whether the proportion of chips do not fail in the first 1000 hours of their use is 52% or not.

The hypothesis can be defined as:

<em>H₀</em>: The proportion of chips do not fail in the first 1000 hours of their use is 52%, i.e. <em>p</em> = 0.52.

<em>Hₐ</em>: The proportion of chips do not fail in the first 1000 hours of their use is different from 52%, i.e. <em>p</em> ≠ 0.52.

The information provided is:

\hat p=0.49\\n=900\\\alpha =0.02

The test statistic value is:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.49-0.52}{\sqrt{\frac{0.52(1-0.52)}{900}}}=-1.80

The test statistic value is -1.80.

Decision rule:

If the <em>p-</em>value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the <em>p</em>-value as follows:

p-value=2\times P(Z

*Use a <em>z</em>-table.

The <em>p</em>-value = 0.07186 > <em>α</em> = 0.02.

The null hypothesis was failed to be rejected at 2% level of significance.

<u>Conclusion</u>:

The proportion of chips that do not fail in the first 1000 hours of their use is 52%.

8 0
3 years ago
According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m
tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

x/4 = 0.25x of 1/5 = 0.2(very active). So

P(A) = 0.8x + 0.25*0.2x = 0.85x

Probability of developing diabetes while being very active:

0.25x of 0.2. So

P(A \cap B) = 0.25x*0.2 = 0.05x

What is the probability that a middle-aged man with diabetes is very active?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.05x}{0.85x} = \frac{0.05}{0.85} = 0.0588

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

4 0
3 years ago
Solve z = 8 + 6x - px for x
bearhunter [10]

Answer:

p = 7, x = 8

Step-by-step explanation:

z=8+6x-px for x

x = (8 - z)/(p - 6) and p≠6

Integer Roots:

p = -2, x = -1

p = 7, x = 8

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3 years ago
Help i’ll mark brainliest
Agata [3.3K]

Answer:

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7 0
3 years ago
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