The given dimensions of 9.5, 6, 7, and 6.5 cm gives the following
perimeter and area of the trapezium.
<h3>How can the area and perimeter of the trapezium be found?</h3>
The perimeter of a trapezoid is given as follows;
Perimeter = The sum of the lengths of the sides
Which gives;
Perimeter = 6 + 7 + 6.5 + 9.5 = 29
The perimeter of the trapezoid =<u> 29 cm</u>
The area of the trapezoid is given as follows;
![Area = \mathbf{ \dfrac{Sum \ of \ the \ parallel \ sides }{2} \times Height}](https://tex.z-dn.net/?f=Area%20%3D%20%5Cmathbf%7B%20%5Cdfrac%7BSum%20%5C%20of%20%5C%20the%20%5C%20parallel%20%5C%20sides%20%7D%7B2%7D%20%5Ctimes%20Height%7D)
Which gives;
![Area = \dfrac{7 + 9.5 }{2} \times 6 = 49.5](https://tex.z-dn.net/?f=Area%20%3D%20%5Cdfrac%7B7%20%2B%209.5%20%7D%7B2%7D%20%5Ctimes%206%20%3D%2049.5)
The area of the trapezoid = 49.5 cm²
Learn more about the area and perimeter of geometric shapes here:
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brainly.com/question/11461461
Answer:
Below in bold.
Step-by-step explanation:
Area of a kite = 1/2 * D1 * D2 were D1 and D2 are the 2 diagonals
D1 = 5 + 2.5 = 7.5 and D2 = 2*44444.5 = 9
So area = 1/2 * 7.5 * 9
= 33.75.
Answer: x=55 y=145
x=55
35+90=125
125-180=55
y=145
180-35=145
I hope this is good enough:
Answer:
just write the numbers of coins a different way