12% Of 79 Would be 9.48. Hope this helped :)
Answer:
<em>Most likely time, </em>according to PERT (Program evaluation and review technique).
Step-by-step explanation:
PERT is "a statistical tool used in <em>project management" (Program evaluation and review technique (2020), </em>in Wikipedia), and it is commonly used with CPM <em>(Critical Path Method)</em> to manage projects.
Inside PERT, there are different defined times to accomplished an activity in a project, that is:
- An <em>optimistic time</em> or minimum time required to accomplished an activity, i.e., if everything goes better than normal, the activity is accomplished before expected.
- A <em>pessimistic time, </em>a time quite the opposite to optimistic time.
- A <em>most likely time</em>, or a time required to accomplished an activity if everything goes as expected or normally.
- An <em>expected time</em>, an statistical estimation.
Considering the question, we have that the <em>time</em> when "the first module of the project could be completed":
- "[...] in as few as 15 days" is the <em>optimistic time</em>.
- "[...] or could take as many as 25 days" is the <em>pessimistic time</em>.
- "[...] but most likely will require 20 days" is the <em>most likely time</em>.
As a result, the <em>20-day estimate</em> is called the <em>most likely time</em> in the context of the PERT/CPM techniques.
Answer:
Step-by-step explanation:
Here we are given two coordinates through which our lines passes through. Now we are going to use the two point form to find the equation of the line.
The two point form is given as
Here we are given two coordinates . Thus replacing them in the formula and simplifying it will give us the equation of the line.
adding x and 6 on both sides we get
Hence this is our equation of the line passing through (5,6) & (4,7)
The best step to do next is to add 80 to both sides of equation:
5 ( x² + 8 x ) + 80 = 14 + 80
and since 80 = 5 · 16
5 ( x² + 8 x + 16 ) = 94 Answer : B )
After that we will continue like this:
5 ( x + 4 )² = 94
( x + 4 )² = 18.8 ... etc
