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3 years ago

Answer: 98 For what is the value of X

Mathematics

1 answer:

Sholpan [36]3 years ago

6 0

well whats the question??? lolololol

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I WILL MARK BRAINLIEST J PLS ANSWER

trapecia [35]

Answer:

small jets 213 large 632

Step-by-step explanation:

7 0

2 years ago

PLEASE HELP 25 POINTS!!

eduard

Answer:

(27 y^(-8))/(4 x^6)

Step-by-step explanation:

Simplify the following:

(4 (3 x^2 y^4)^3)/(2 x^3 y^5)^4

Multiply each exponent in 2 x^3 y^5 by 4:

(4 (3 x^2 y^4)^3)/(2^4 x^(4×3) y^(4×5))

4×5 = 20:

(4 (3 x^2 y^4)^3)/(2^4 x^(4×3) y^20)

4×3 = 12:

(4 (3 x^2 y^4)^3)/(2^4 x^12 y^20)

2^4 = (2^2)^2:

(4 (3 x^2 y^4)^3)/((2^2)^2 x^12 y^20)

2^2 = 4:

(4 (3 x^2 y^4)^3)/(4^2 x^12 y^20)

4^2 = 16:

(4 (3 x^2 y^4)^3)/(16 x^12 y^20)

Multiply each exponent in 3 x^2 y^4 by 3:

(4×3^3 x^(3×2) y^(3×4))/(16 x^12 y^20)

3×4 = 12:

(4×3^3 x^(3×2) y^12)/(16 x^12 y^20)

3×2 = 6:

(4×3^3 x^6 y^12)/(16 x^12 y^20)

3^3 = 3×3^2:

(4×3×3^2 x^6 y^12)/(16 x^12 y^20)

3^2 = 9:

(4×3×9 x^6 y^12)/(16 x^12 y^20)

3×9 = 27:

(4×27 x^6 y^12)/(16 x^12 y^20)

4/16 = 4/(4×4) = 1/4:

(27 x^6 y^12)/(4 x^12 y^20)

Combine powers. (27 x^6 y^12)/(4 x^12 y^20) = (27 x^(6 - 12) y^(12 - 20))/4:

(27 x^(6 - 12) y^(12 - 20))/4

6 - 12 = -6:

(27 x^(-6) y^(12 - 20))/4

12 - 20 = -8:

Answer: (27 y^(-8))/(4 x^6)

5 0

4 years ago

When subtracting 9.3 from a certain number, the result is 68.91, as seen below. What number should go in the box to complete the

Vaselesa [24]

Answer: 68.91 + 9.3 = 78.21

4 0

3 years ago

Read 2 more answers

Which pair of complex factors results in a real-number product?

Crank

we will proceed to solve each case to determine the solution of the problem

we know that

$i^{2} =-1$

case A. $15*(-15i)$

$15*(-15i)=-225i$

The result of case A is not a real number product

case B. $3i*(1-3i)$

$3i*(1-3i)=3i*(1)-(3i)*(3i)\\=3i-9i^{2}\\=3i-9*(-1)\\=3i+9$

The result of case B is not a real number product

case C. $(8+20i)*(-8-20i)$

$(8+20i)*(-8-20i)=8*(-8)+8*(-20i)+20i*(-8)-20i*(20i)\\=-64-160i-160i-400i^{2}\\=-64-320i-400*(-1)\\=-64-320i+400\\=336-320i$

The result of case C is not a real number product

case D. $(4+7i)*(4-7i)$

$(4+7i)*(4-7i)=4^{2} -(7i)^{2}\\=16-49i^{2}\\=16-49*(-1)\\=65\\$

The result of case D is a real number product

therefore

the answer is the option

$(4+7i)*(4-7i)$

8 0

3 years ago

Read 2 more answers

14xy – 13 - xy – 22x – 20= I really need help with this question

Aliun [14]

I'm sorry I'm not home so I can't tell you the answer to this but what I can tell you is put together the xy and then put together the -13-20. Hope this helps.

4 0

4 years ago

Read 2 more answers