What is the LCD of 11/12 and 1/8
2 answers:
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<h2>Dionne will fold 210 packing boxes in "60 mìnutes" and</h2><h2>Elias will fold 210 packing boxes in "70 mìnutes".</h2>
Step-by-step explanation:
Given,
Dionne can fold 175 packing boxes = 50 mìnute and
Elias can fold 120 packing boxes = 40 minutes
To find, the total time each person to fold 210 packing boxes = ?
∵ Dionne can fold 175 packing boxes = 50 mìnute
∴ In 1 mìnute, Dionne can fold number of packing boxes = = 3.5
∴ Dionne can fold 210 packing boxes = minutes
= 60 minutes
Also,
Elias can fold 120 packing boxes = 40 minutes
∴ In 1 mìnute, Elias can fold number of packing boxes = = 3
∴ Elias can fold 210 packing boxes = minutes
= 70 minutes
Thus, Dionne will fold 210 packing boxes in "60 mìnutes" and
Elias will fold 210 packing boxes in "70 mìnutes".
Answer:
The Distance cover by both the Runners is same = 10 miles
Step-by-step explanation:
According to question ,
The Speed of first runners (S 1) = 5 miles per hour
The speed of second runners (S 2) = 4 miles per hour
Let The Time taken by First runner (T 1 ) = T hour
But the second runner arrives half hour after the first runner ,
I.e The Time taken by Second runner (T 2) = ( T + )
Now from Distance = Speed × Time
Since both the runners start from same place and run along the same trail
SO ,Both the Distance cover by both are same , D 1 = D 2
i.e Speed 1 × Time 1 = Speed 2 × Time 2
5 mph × T = 4 mph × ( T + )
5 T = 4 T + ( 4 × )
Or, 5 T - 4 T = 2
∴ T = 2 hour ,
Time take by first = T1 = T = 2 hour
Time take by second = T2 = T + = (2 +
)hour =
Now the Distance cover = Speed × Time
Distance (D1) = 5 mph × 2 hour = 10 mile
And Distance (D2) = 4 mph × = 10 miles
Hence, As The Distance cover by both the Runners is same = 10 miles Answer
For this case we must solve the following linear equation:
Adding similar terms from the left side of the equation:
Subtracting from both sides of the equation we have:
Thus, equality is not fulfilled. So the equation has no solution.
Answer:
No solution