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TEA [102]
2 years ago
14

Which of the following represents an equation in standard form for the line that passes through (3, −1) and (−5, −3).

Mathematics
1 answer:
kotegsom [21]2 years ago
6 0

Answer:

  • y = ¼x + (-7/4)

Step-by-step explanation:

find the gradient ( M)

M = y2- y1 ÷ x2-x1

M= -3 - (-1)÷(-5)-3 = ¼

<h3>the </h3>

find C in the equation (y=mx+c)

<h3>C = y-mx ( C = -1-¼(3)= -7/4</h3>

(use in y and x values provided)

now replace the values you find in the equation (y=Mx+C)

final answer is

<h3>y = ¼x+(-7/4)</h3>
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What is the simplified form of the expressions?<br> a. −6a2b−1 <br> b. 5/y−3
Karo-lina-s [1.5K]

Answer:

a.

-6a²/ b

b.

5y³

Step-by-step explanation:

a

-6a²b⁻¹

-6a²/ b

b.

5/ y⁻³

5 / 1/ y³

5 * y³/1

5y³

8 0
3 years ago
You randomly pick two numbers from 1 to 9 (including 1 and 9). A number that is chosen once could be chosen again. If at least o
Mnenie [13.5K]
Assume that you only include whole numbers (1,2,3,4,5,6,7,8,9) and not 3.5 and such
so if 1 is odd and less than 5 then it is
1 or 3, since 5 isn't included
then the other number, to be less than 5 when added,
must be
1+x<5
3+x<5
solve each
1+x<5
subtract 1
x<4
set of answers are 1,2,3

3+x<5
subtract 3
x<2
set of answer is 1
so the possible numbers are
1,2,3
that is 3 numbesr out of 9 so
probability=(total desired outcomes)/(total possible outcomes) so
disred outcomes=3
total possible=9
3/9=1/3
the probabiltiy is 1/3
7 0
3 years ago
Suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.5
masya89 [10]

Answer:

z= \frac{3.44-2.54}{0.45}=2

P(X>3.44) = P(Z>2) = 0.025

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the grade points avergae of a population, and for this case we know the following properties

Where \mu=2.54 and \sigma=0.45

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

So we can find the z score for the value of X=3.44 in order to see how many deviations above or belowe we are from the mean like this:

z= \frac{3.44-2.54}{0.45}=2

So the value of 3.44 is 2 deviations above from the mean, so then we know that the percentage between two deviations from the mean is 95% and on each tail we need to have (100-95)/2 = 2.5% , because the distribution is symmetrical, so based on this we can conclude that:

P(X>3.44) = P(Z>2) = 0.025

5 0
3 years ago
What is W in this equation <br> -w–11≤w–5
zhannawk [14.2K]

Step-by-step explanation:

-w - 11 < or = w - 5

-2w - 11 < or = -5

-2w < or = -16

w > or = -8

5 0
3 years ago
Find the slope of the line #3 and 4 please:))
Leokris [45]

Answer:

#3 - y=4

#4 - x=-1

Step-by-step explanation:

With #3 you are only puting the y-value.

With #4 you are only putting the x-value.

5 0
4 years ago
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