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2 years ago

Which of the following represents an equation in standard form for the line that passes through (3, −1) and (−5, −3).

Mathematics

1 answer:

kotegsom [21]2 years ago

6 0

Answer:

y = ¼x + (-7/4)

Step-by-step explanation:

find the gradient ( M)

M = y2- y1 ÷ x2-x1

M= -3 - (-1)÷(-5)-3 = ¼

find C in the equation (y=mx+c)

(use in y and x values provided)

now replace the values you find in the equation (y=Mx+C)

final answer is

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Help I don’t know it

Vladimir [108]

Answer:

use socratic

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the

maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

$y=ax^2+bx+c$

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

$x_v=-\frac{b}{2a}$

In this problem, we have:

$y=-x^2-6x-13$

Then:

a = -1

b = -6

We write now:

$x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3$

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

$-x^2-6x-13=0$

To solve this, we can use the quadratic formula:

$x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}$

And solve:

$x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}$ $x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}$

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

$y=-0^2-6\cdot0-13=-13$

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

$x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20$ $x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8$

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

$y=-(-3)^2-6(-3)-13=-9+18-13=-4$

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0

1 year ago

The table shows a cricket club's income in 2016 from a fete, a quiz and membership fees.

kirill [66]

Answer: 5:2:10

Income from fete = £250

13 x 5 + 35 = 100

25 x 20 = 500

250:100:500

Then simplify ratio -

25:10:50

5:2:10

8 0

3 years ago

The surface area of an oil spill gets 131% larger every day, represented by the function s(x) = (1.31)x − 1. On the first day, i

scoray [572]

Answer:

The correct option is B.

Step-by-step explanation:

It is given that the surface area of an oil spill gets 131% larger every day, represented by the function

Where x is number of days.

On the first day, it covered an area of 21 square meters. It means the initial area is 21 square meters.

The function is defined as

Where is initial value and b is growth factor.

It means the function of new area is the product of initial area and increasing area function. The required function is

Therefore option B is correct.

6 0

3 years ago

Identify the leading coefficient in the following polynomial:<br> – 5x² + 3x - 7

insens350 [35]

Answer:

-5

Step-by-step explanation:

The leading coefficient means the thing you're multiplying your highest power by. Here, your highest power of x is x^2, and that term's coeff. is -5, so the leading coefficient is -5.

7 0

3 years ago