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2 years ago

Which of the following represents an equation in standard form for the line that passes through (3, −1) and (−5, −3).

Mathematics

1 answer:

kotegsom [21]2 years ago

6 0

Answer:

y = ¼x + (-7/4)

Step-by-step explanation:

find the gradient ( M)

M = y2- y1 ÷ x2-x1

M= -3 - (-1)÷(-5)-3 = ¼

find C in the equation (y=mx+c)

(use in y and x values provided)

now replace the values you find in the equation (y=Mx+C)

final answer is

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⚡️⚡️Really need help, would appreciate it⚡️⚡️

pentagon [3]

Answer:

The answer to your question is letter A. Regular size is cheaper than Economy size by $0.0003 per gram

Step-by-step explanation:

Cost of 1 gr of economy size

5000 gr (5 kg) ------------------- $ 5.15

1 gr -------------------- X

x = 1 x 5.15 / 5000 = $0.0010

Cost of 1 gr of regular size

820 gr ------------------- $0.60

1 gr -------------------- x

x = 1 x 0.6 / 820 = $ 0.0007

Difference of cost = $0.0010 - $0.0007 = $0.0003

3 0

3 years ago

If r = 8 units and h = 10 units, what is the volume of the cylinder shown above? use 3.14 for pi,

Basile [38]

I hope this helps you

Volume =pi.r^2.h

Volume =3,14.8^2.10

Volume =31,4.64

Volume =200,96

8 0

2 years ago

What is 8,100 in scientific notation?

Rzqust [24]

8.1 I think but there's an app called, tiger something and it tells,you the answers

6 0

3 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

2 years ago

Using the information given, calculate a grade to the nearest whole percent. The "rise" is 525 feet. If the scale on the map sho

melamori03 [73]

The grade on the west side would be the vertical rise divided by the horizontal run or 525 divided by 800' or rounded off to 66% (a steep grade as in an underground mine a grade of 25% is considered very steep for vehicles to go up or conveyors to travel). On the east side the 40% grade was obtained by dividing the 525' vertical height by the 1300' run.

5 0

3 years ago

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