Square root 50 does not belong....all of the other numbers are rational numbers. square root 50 is irrational.
he will be reimbursed 137.26 dollars for two days
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Explanation:</h2><h2>
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The diagram is missing but I'll assume that the arc BDC is:

And another arc, let's call it FGH. measures:

If those arc are equal, then this equation is true:

Substituting k into the first equation:

30.
3/4 is equal to 75%, so take 75% of 40 by multiplying .75 by 40 to get 30
To solve an equation with a rational (fraction) coefficient you need to multiply both sides of the equation by the reciprocal (invert the fraction - flip it).

The reciprocal of 1/6 is 6/1 or 6

The product of reciprocals equals 1
1x = 24
x = 24