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s2008m [1.1K]
4 years ago
5

Which postulate or theorem, if any, could be used to prove the triangles congruent? If not

Mathematics
2 answers:
inysia [295]4 years ago
7 0
Question 11a)

We are given side BC equals to side CE and angle CBA equals to angle CED
We also know that angle ACB equals to angle ECD are equal (opposite angles properties)

We have enough information to deduce that triangle ABC and triangle CDE are equal by postulate Angle-Side-Angle (ASA)

---------------------------------------------------------------------------------------------------------------

Question 11b)

We are given side AB equal to side ED, side BC equals to side EF, and side AC equals to side DF
We have enough information to deduce that triangle ABC and triangle DEF congruent by postulate Side-Side-Side (SSS)

----------------------------------------------------------------------------------------------------------------

Question 11c)

We are given side AC equals to side DF, angle ABC equals to angle DEF, and angle BAC equals to angle EDF

We have enough information to deduce that triangle ABC congruent to triangle DEF by postulate Angle-Side-Angle (ASA)

-----------------------------------------------------------------------------------------------------------------

Question 11d)

We do not have enough information to tell whether this shape congruent or not
ollegr [7]4 years ago
3 0

Answer: on d. it's, you

weren;t given enough information

Step-by-step explanation:

ur welcome.

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In the data table shown, if x = 20, then y=
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Answer:

we need the table!

Step-by-step explanation:

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4 years ago
Read 2 more answers
20 POINTS!!!!!!!
zavuch27 [327]
So the first one is -0.5 and second is -0.5 the third one is -0.5 and the fourth is -0.25 so I would say that is D
8 0
3 years ago
In a taste test, each sample serving of a new drink is about 50 milliliters The drink comes in a 1 liter
expeople1 [14]

Answer:

Step-by-step explanation:

it is 25 25+125=50

7 0
3 years ago
Can u pls give a clear explanation & word it out how u got the answer without using big words. Thank u
gizmo_the_mogwai [7]

A.

We can rewrite the squared in two ways.

The first way is to rewrite it as a multiplication, this is:

(y-6)^2=(y-6)(y-6)

The second way to rewrite the squared is by using the formula for this kind of product:

(y-6)^2=y^2+2(-6)(y)+(-6)^2

B.

Once again we can find the final result using each of the options given in part A, for the first option we have:

\begin{gathered} (y-6)^2=(y-6)(y-6) \\ =y^2-6y-6y+36 \\ =y^2-12y+36 \end{gathered}

For the second option we have:

\begin{gathered} (y-6)^2=y^2+2(-6)(y)+(-6)^2 \\ =y^2-12y+36 \end{gathered}

No matter which way we choose the answer for the squared is:

y^2-12y+36

3 0
1 year ago
46 POINTS!!!
charle [14.2K]

Answer:

<h2><u>r = -0.4</u></h2>

Step-by-step explanation:  57.7r + 23.23 = 2.57          57.7/57.7  = -20.66/57.7

                                                        - 23.23  - 23.23                      

                                              57.7r = -20.66

6 0
3 years ago
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