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sveticcg [70]
3 years ago
5

the population density of themville is 17.5 thems per acre. Exactly 840 thems live in themville how many acress if themville

Mathematics
1 answer:
postnew [5]3 years ago
8 0
I believe the answer you are looking for is 840 ÷ 17.5 which is 48 acres.
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What is the answer ?
fomenos

Answer:

19/60 or .317

Step-by-step explanation:

C = 95/300

95/300 = 19/60

19/60 = .317

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2 years ago
Use the dchnition of similarity to solve the following problem.
sveta [45]

Answer:

  1063 ft

Step-by-step explanation:

For shadow problems, we assume the sun's rays are parallel, so the triangles formed are similar. That means the ratio of height to shadow length is the same for each object.

  h/(580 ft) = (5.5 ft)/(3 ft)

  h = (5.5 ft)(580/3) ≈ 1063 ft

The height of the monument is about 1063 feet.

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2 years ago
A regional airport, community college, and city hall building are located at the vertices
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Step-by-step explanation:

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3 years ago
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saul85 [17]

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6 0
2 years ago
Read 2 more answers
Secants L J and L M intersect and form an angle at point L. Solve for x.
german

Answer:

x = 14  

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

It checks.

6 0
3 years ago
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