Given
R is the interior of ∠ TUV.
m∠ RUV=30degrees, m∠ TUV=3x+16, and m∠ TUR=x+10.
Find the value of x and the m ∠TUV.
To proof
As given in the question
m ∠TUV=3x+16, and m ∠TUR=x+10
thus
m∠ RUV = m∠ TUV - m∠ TUR
= 3x + 16 - x -10
= 2x + 6
As given
m ∠RUV=30°
compare both the values
we get
30 = 2x + 6
24 = 2x
12 = x
put this value in the m ∠TUV= 3x+16
m ∠TUV= 12× 3 +16
= 52°
Hence proved
I would convert them all to the denominator 16, due to the smallest fraction and all of them can be converted to it.
1 = 16/16
1/2 = 8/16
1/4 = 4/16
1/8 = 2/16
1/16 = 1/16
1+ 2 + 4 + 8 + 16 = 31
31/16 = 1 15/16
Hope this helps!
Given:
A student says that the graph of the equation
is the same as the graph of
, only translated upwards by 8 units.
To find:
Whether the student is correct or not.
Solution:
Initial equation is


Equation of after transformation is


Now,
...(i)
The translation is defined as
...(ii)
Where, a is horizontal shift and b is vertical shift.
If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.
From (i) and (ii), we get

Therefore, the graph of
translated left by 8 units. Hence, the student is wrong.
10P8 = 10!/(10 - 8)! = 10!/2! = 1,814,400
Answer: a) (176.76,172.24), b) 0.976.
Step-by-step explanation:
Since we have given that
Mean height = 174.5 cm
Standard deviation = 6.9 cm
n = 50
we need to find the 98% confidence interval.
So, z = 2.326
(a) Construct a 98% confidence interval for the mean height of all college students.

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?
Error would be

Hence, a) (176.76,172.24), b) 0.976.