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Nikitich [7]
4 years ago
15

(x+3)*2 =4 please help

Mathematics
1 answer:
Ostrovityanka [42]4 years ago
5 0

2x+2*3=4

2x+6=4

2x=-2

x=-1

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Please help!!!
IrinaK [193]

Answer:

it would be $16 off 40 so the pants would be $24

3 0
3 years ago
Which set of fractions is equal? 1/2=6/14 1/3=3/6 3/4=6/8 1/6=3/12
Evgen [1.6K]

Answer:

3/4=6/8

Step-by-step explanation:

This is equal because 3/4 + 3/4 = 6/8. So this is your answer.

Hope this helped! :) Have a good day!!

8 0
3 years ago
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830000 in scientific notation
Pavlova-9 [17]

Answer:

8.3 * 10 ^5

Step-by-step explanation:

830000

To change this to scientific notation, we move the decimal 5 places to the left.  The exponent will be positive 5 because we moved it to the left

8.3 * 10^ +5

8.3 * 10 ^5

4 0
4 years ago
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Prove De Morgan's law by showing that each side is a subset of the other side by considering x ∈ A⎯⎯⎯ A ¯ ∩ B⎯⎯⎯ B ¯ .
adelina 88 [10]

Solution :

We have to prove that $\overline{A \cup B} = \overline{A} \cap \overline{B}$   (De-Morgan's law)

Let  $x \in \bar{A} \cap \bar{B}, $ then $x \in \bar{A}$ and $x \in \bar{B} $

and so $x \notin \bar{A}$ and $x \notin \bar{B} $.

Thus, $x \notin A \cup B$ and so $x \in \overline{A \cup B}$

Hence, $\bar{A} \cap \bar{B} \subset \overline{A \cup B}$   .........(1)

Now we will show that $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$

Let $x \in \overline{A \cup B}$ ⇒ $x \notin A \cup B$

Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.

$x \in \overline{A}$ and  $x \in \overline{B}$

Therefore, $x \in \overline{A} \cap \overline{B}$ and we have $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$  .............(2)

From (1) and (2),

$\overline{A \cup B} = \overline{A} \cap \overline{B}$

Hence proved.

3 0
3 years ago
Ethan earns 64.00 in a day. If a month has 22<br> work days, then what is Ethan's monthly pay?
MAXImum [283]

Answer:

$1408

Step-by-step explanation:

64 * 22 = 1408

5 0
3 years ago
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