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rewona [7]
3 years ago
8

Please help!!!

Mathematics
1 answer:
IrinaK [193]3 years ago
3 0

Answer:

it would be $16 off 40 so the pants would be $24

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HELP!!! 40 PTS!<br><br> What is its area? Show your work
Vadim26 [7]

a is height p is perimeter

6 0
3 years ago
Find the value of the expression 0.5^10/0.5^7
SIZIF [17.4K]

Answer:

The solution is:

  • \frac{0.5^{10}}{0.5^7}=0.125

Step-by-step explanation:

Given the expression

0.5^{10}\div 0.5^7

Solving

\frac{0.5^{10}}{0.5^7}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

so

\frac{0.5^{10}}{0.5^7}=0.5^{10-7}

\mathrm{Subtract\:the\:numbers:}\:10-7=3

=0.5^3

=0.125        ∵ 0.5^3=0.125

Therefore, the solution is:

\frac{0.5^{10}}{0.5^7}=0.125

7 0
3 years ago
Point m is the midpoint of kL. M(1,-1) and L(8,-7. What are the coordinates of point k?
Phoenix [80]

Answer: (-6, 5)

<u>Step-by-step explanation:</u>

Use the Midpoint Formula: \dfrac{(x_k, y_k)+(x_L,y_L)}{2}=(x_m, y_m)

Separate the x's and y's and solve them individually:

\dfrac{x_k+x_L}{2}=x_m\qquad \qquad \qquad \qquad\dfrac{y_k+y_L}{2}=y_m\\\\\\\dfrac{x_k+8}{2}=1\qquad \qquad \qquad \qquad \qquad \dfrac{y_k-7}{2}=-1\\\\\\x_k+8=2\qquad \qquad \qquad \qquad \qquad y_k-7=-2\\\\\\x_k\quad =-6 \qquad \qquad \qquad \qquad \qquad y_k\qquad =5

            So, the k-coordinate is (-6, 5)

3 0
3 years ago
Simplify the following: (-83)2​
Anika [276]
The answer is -166, your welcome
8 0
2 years ago
The graph of the function f(x) = log2x is shown.
jekas [21]

The domain of the function g(x) = 2 log₂(x - 4) + 3 will be (4, ∞). Then the correct option is A.

<h3>What are domain and range?</h3>

The domain means all the possible values of x and the range means all the possible values of y.

The graph of the function f(x) = log₂x is shown.

Function g is defined as g(x) = 2f(x - 4) + 3.

Then the function g(x) will be

g(x) = 2 log₂(x - 4) + 3

Then the domain of the function g(x) will be (4, ∞).

Then the correct option is A.

More about the domain and range link is given below.

brainly.com/question/12208715

#SPJ1

7 0
2 years ago
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