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3 years ago

Please help!!!

Mathematics

1 answer:

IrinaK [193]3 years ago

3 0

Answer:

it would be $16 off 40 so the pants would be $24

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Given that -6,-6 is on the graph of f x find the corresponding point for the function f(3/4x)

Liono4ka [1.6K]

Answer:

The corresponding point is (-8, -6).

Step-by-step explanation:

Given that

(-6,-6) lies on the graph of $f(x)$

A function is represented in the form:

$y = f(x)$

i.e. (-6,-6) means value of x = -6 is put and value y came out as -6.

$f(-6) = -6$

Now, we have to find the corresponding point on $f(\frac{3}{4}x)$ .

We know the value of $f(-6)$

Let us find the value of x where $\frac{3}{4}x$ becomes equal to -6

$\dfrac{3}{4}x=-6\\\Rightarrow 3x=-24\\ \Rightarrow x =-8$

So, let us put value of $x = -8$ in $f(\frac{3}{4}x)$ :

$f(\frac{3}{4}\times (-8))\\\Rightarrow f(3\times (-2))\\\Rightarrow f(-6) = -6$ (as per given statement)

So, the corresponding point is (-8, -6).

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3 years ago

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Lera25 [3.4K]

Answer:

1:1

Step-by-step explanation:

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3 years ago

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3 years ago

4)11,717,555 the one is underlined and i need to know the place value of it

Fiesta28 [93]

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4 years ago

Read 2 more answers

A factory is to be built on a lot measuring 210 ft by 280 ft. A local building code specifies that a lawn of uniform width and e

Tresset [83]

Answer:

Width of lawn = 35 ft

Dimensions of factory = length: 210 ft, width: 140 ft

Step-by-step explanation:

The total area of the lot can be calculated as:

$A_{lot} = 210 * 280\\A_{lot} = 58800 ft^{2}$

Since, the area of factory should be equal to area of lawn:

$A_{lot} = A_{factory} + A_{lawn}\\58800 = 2 A_{factory or lawn}\\\\A_{factory or lawn} = \frac{58800}{2}\\A_{factory or lawn} = 29400 ft^{2}$

Now, let 'x' be the width of lawn, the dimensions of factory can be written as:

$(210-2x)\\(280-2x)\\$

Since, area is equal to length x width:

$(210-2x)*(280-2x) = 29400\\Simplifying:\\210*280 - 210*2x - 2x*280 + 4x^{2} = 29400\\58800 - 420x - 560x +4x^{2} = 29400\\4x^{2} - 980x +58800 = 29400\\4x^{2} - 980x + 29400 = 0\\$

Divide whole equation by 4,

$x^{2} - 245 + 7350 = 0\\$

Solving above quadratic equation, we get,

$x = 210\\x = 35\\$

x = 35 seems realistic width of the lawn.

Now, finding the dimension of factory:

$(210-2x) = 210 - 2(35) = 140 ft\\(280-2x) = 280 - 2(35) = 210ft$

We can also reconfirm the area of factory by multiplying the above two lengths:

140 * 210 = 29400 ft

8 0

3 years ago