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3 years ago

HELP WITH ALGEBRA 1

Mathematics

1 answer:

storchak [24]3 years ago

8 0

Part A:we know p(t)=6t and also
A(p)=πp2replace p by 6t
A(t)=π(6t)2=36πt2Part B = 7234.56

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EASY MATH PLEASE HELP!

zhenek [66]

Answer:

40 Percent

Step-by-step explanation:

7 0

2 years ago

Robert earns $498.00 for 40 hours of work. How much does he earn if works 30 hours at the same pay rate? Do not round your answe

elena55 [62]

Answer:$373.50

Step-by-step explanation:

$498.00 divided by 40 is 12.45

12.45 times 30 is $373.50

7 0

2 years ago

Read 2 more answers

Answer if you can and help other people out

oksano4ka [1.4K]

<h2>Answer:</h2><h2>131.964 cm</h2>

Solution,

radius=21 cm

Circumference of circle=2 pi r

 =2*3.142*21

 =131.964 cm

hope it helps

Good luck on your assignment

8 0

3 years ago

Read 2 more answers

Resuelve los problemas de una bodega que exporta tomates al extranjero

Dovator [93]

Answer:

1. 34.42 Toneladas

2. 28.640 toneladas

3. 38 toneladas

4. $\frac{15}{10}$ o $1\frac{5}{10}$

5. $\frac{16}{6}$ o $2\frac{4}{6}$

6. $\frac{8}{4}$ o $2$

1.1 Solucioné el problema convirtiendo el .25 en fracción.

2.1 Conviertes el denominador en el mismo buscando el minimo comun multiplo

3.1 0.099

$\frac{1}{4}$

$\frac{1}{3}$

$\frac{2}{3}$

0.7

0.75

1.1

$\frac{3}{2}$

Step-by-step explanation:

Acuerdate que para solucionar las fracciones mixtas solo tienes que dividir el denominador al nominador, por ejemplo en si tienes $\frac{10}{3}$ entonces el 3 cabe 3 veces en el 10, y sobra 1, entonces quedamos que en mixta la fracción sería $3\frac{1}{3}$

Entonces una vez que recordamos eso, podemos resolver los problemas de fracciones sin ningún problema vamos a resolver la número 4:

$\frac{8}{10} +\frac{7}{10}$

Como el denominador es igual, sólo sumamos el nominador:

$\frac{8+7}{10}$

$\frac{15}{10}$

Cómo el 10 cabe 1 vez en el 15, tenemos un entero y sobran 5:

$1\frac{5}{10}$

5 0

3 years ago

Find the area of the circle whose equation is x2+y2=6x-8y

Semenov [28]

Answer:

Given that the equation of a circle is :

$\green{ \boxed{\boxed{\begin{array}{cc} {x}^{2} + {y}^{2} = 6x - 8y \\ = > {x}^{2} + {y}^{2} - 6x + 8y = 0 \\ = > {x}^{2} + {y}^{2} + 2 \times ( - 3) \times x + 2 \times 4 \times y = 0 \\ \\ \sf \: standard \: equation \: o f \: circle \: is : \\ {x}^{2} + {x}^{2} + 2gx + 2fy + c = 0 \\ \\ \sf \: by \: comparing \\ \\ g = - 3 \\ f = 4 \\ c = 0 \\ \\ \sf \: radius \: \: r = \sqrt{ {g}^{2} + {f}^{2} - c } \\ = \sqrt{ {( - 3)}^{2} + {4}^{2} - 0 } \\ = \sqrt{9 + 16} \\ = \sqrt{25} \\ = 5 \: unit \\ \\ \bf \: area \: = \pi {r}^{2} \\ = \pi \times {5}^{2} \\ =\pink{ 25\pi \: { unit }^{2} }\end{array}}}}$

6 0

3 years ago